Two blocks on a frictionless surface; find the force

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Two blocks, A and B, are pushed on a frictionless surface by a total force of 30 N. Block A has a mass of 2.0 kg, while Block B has a mass of 4.0 kg. The force exerted by Block B on Block A is calculated to be 20 N, based on the acceleration derived from the total force. Using Newton's second law, the same acceleration applies to both blocks, confirming the force needed to accelerate Block B is indeed 20 N. According to Newton's third law, Block B exerts an equal and opposite force of 20 N on Block A.
Peter Halsall
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Homework Statement


Two blocks, A and B , are being pushed on a frictionless surface by a froce of 30 N to the right, .Block A has a mass of 2.0kg, Block B, being pushed by Block A is 4.0kg. Calculate the magnitude of the force that block B exerts on Block A.

Homework Equations


f=ma

The Attempt at a Solution


If The total force pushing the blocks as a system is 30 N, then if you treat the objects as individuals 20 N of the force is provided by Block B and 10 N by Block A. So 20 N is the magnitude of the force that Block B exerts on Block A
 
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Is fine, but can you express it more formally in terms of ##F = ma## for the ensemble and for each of the blocks ?
 
BvU said:
Is fine, but can you express it more formally in terms of ##F = ma## for the ensemble and for each of the blocks ?
I'm sorry, I don't understand what your asking, do you want me to prove it using Newton's 2nd law?
 
Yes. F = ma for the total, a is the same for A and B so with F = ma for B the force needed to accelerate B is the 20 N you found. And from Newton 3 B exerts a reaction force of the same magnitude on A.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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