Two blocks on top of each other

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Homework Help Overview

The problem involves two blocks, one resting on top of the other, with a tension force applied to the lower block. The scenario includes analyzing the direction of frictional forces and determining the maximum tension before the top block begins to slide. The subject area pertains to dynamics and friction in a physics context.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the direction of the frictional force acting on the top block and its relationship to the motion of both blocks. There are attempts to clarify the forces acting on the blocks and the role of static friction in their movement. Questions arise about the free body diagrams (FBDs) and the interaction between normal and frictional forces.

Discussion Status

Participants are actively engaging with the problem, questioning each other's reasoning and clarifying concepts related to forces and motion. Some guidance has been provided regarding the role of static friction in keeping the blocks together, but there is no explicit consensus on the direction of the frictional force or the approach to the second part of the problem.

Contextual Notes

There are indications of confusion regarding the definitions and roles of normal force and frictional force, as well as the requirement to show attempts before receiving further assistance, in line with forum rules.

fishiiie
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Hi guys, it's my first time posting here so please forgive me for anything wrong!

Homework Statement



A block of mass m = 0.570 kg rests on top of a block of mass M = 2.30 kg. A string
attached to the block of mass M is pulled so that its tension is T = 6.20 N at a 20 degree angle to
the horizontal. The blocks move together. The coefficient of static friction at
the surface between the blocks is μs = 0.43; there is no friction at the surface between
block M and the floor.

a) What is the direction of the frictional force being exerted on the top block of mass m?
Justify your answer.

b) The tension T is now increased - what is the maximum tension, Tmax, with which the string can be pulled such that the blocks continue to move together (i.e. that the block of
mass m does not start to slide on top of the block of mass M)?

Homework Equations



Fnet = ma
Fsmax ≤ μFn

The Attempt at a Solution



a) (Just getting some clarifications on this one to see if I did it right.)
I wrote that friction force should be directed to the left, since static friction (and kinetic friction) always opposes the direction of motion/acceleration.

b) So I'm just trying to draw FBDs for the two blocks and I'm getting confused just doing it. I can't even get the answer if I can't get the FBDs right, so please help me :(

FBDs:
Top block (m):
ƩFx: -Fs = ma
ƩFy: Fn = mg

Bottom block (M):
ƩFx: Tcos20 - Fs = Ma
ƩFy: Fn + Tsin20 = Mg

I'm assuming that both blocks have a normal force on them, but I'm not so sure because I'm getting very confused between normal force and contact force... (Newton's Third Law)

And I'm not sure about the frictional force between the two blocks in the FBDs.. Since it's acting on both blocks (because the friction is between the two blocks), it is included in both of the blocks' FBDs.. right?
 
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Let's tackle a) first. If the static friction opposed the motion of the top block, then what force set it in motion in the first place?
 
The tension in the string? I split the tension T into its components, Tx and Ty ... and I believe this force only acts on the bottom block, not the top.
 
fishiiie said:
I believe this force only acts on the bottom block, not the top.

If that is so, what set the top block in motion?
 
The acceleration, since the acceleration is the same for the two blocks.
 
I don't understand what you're trying to get at, voko.. >< I'm just trying to get the FBDs..
 
Acceleration is a consequence, it is not the cause. When an object begins to move, it will be accelerating just because it begins to move. But what makes an object move, or, more correctly, accelerate?

A force is required to accelerate an object. What forces act on the top block? Which of them makes it accelerate and stay together with the bottom block??
 
voko said:
Acceleration is a consequence, it is not the cause. When an object begins to move, it will be accelerating just because it begins to move. But what makes an object move, or, more correctly, accelerate?

A force is required to accelerate an object. What forces act on the top block? Which of them makes it accelerate and stay together with the bottom block??

I am on this same problem. So let me see if i am on the right track.

Since the bottom block is pulled by the string it will move, and in order for the top of the mass to move, the top mass will have to "stick" with the bottom mass. Therefore the force that makes the top mass stay still and move with bottom mass involves the static friction. Am i correct on this voko?

If yes, then would the forces that makes the top block accelerate are the Ty(tension in the y-axis) + Fs or Ty-Fs?
 
Last edited:
Jabababa said:
Since the bottom block is pulled by the string it will move, and in order for the top of the mass to move, the top mass will have to "stick" with the bottom mass. Therefore the force that makes the top mass stay still and move with bottom mass involves the static friction. Am i correct on this voko?

Yes.

If yes, then would the forces that makes the top block accelerate are the Ty(tension in the y-axis) + Fs or Ty-Fs?

How can the force of tension accelerate the top block if it is not applied to it?
 
  • #10
voko said:
Yes.



How can the force of tension accelerate the top block if it is not applied to it?

so the static friction is the force that makes the top move with the bottom block. Then is the friction force pointing to the right? Sorry I got the concept but still confuse which direction.

Also how do you suggest I tackle on the second question?
 
  • #11
Jabababa said:
Also how do you suggest I tackle on the second question?

According to the rules of the forum, you have to show an attempt.
 

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