Two blocks with different mass

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SUMMARY

The discussion focuses on a physics problem involving two blocks of different masses connected by a light rope over a frictionless pulley. The more massive block descends 1.40 meters, reaching a speed of 1.50 m/s. Using the energy conservation equation K_1 + U_1 + W_other = K_2 + U_2, the mass of the more massive block is calculated to be 11.2 kg, while the lighter block's mass is determined to be 6.8 kg, given a total mass of 18.0 kg.

PREREQUISITES
  • Understanding of kinetic energy (K) and potential energy (U)
  • Familiarity with the conservation of energy principle
  • Basic knowledge of gravitational acceleration (g = 9.8 m/s²)
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Learn about the dynamics of pulleys and tension in ropes
  • Explore the concept of work done by forces in physics
  • Investigate the effects of mass on acceleration in free fall
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the dynamics of systems involving pulleys and mass.

annabelx4
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Two blocks with different mass are attached to either end of a light rope that passes over a light, frictionless pulley that is suspended from the ceiling. The masses are released from rest, and the more massive one starts to descend. After this block has descended a distance 1.40 , its speed is 1.50 .

A. If the total mass of the two blocks is 18.0 , what is the mass of the more massive block?

B. What is the mass of the lighter block?

I know we probably have to use K_1 + U_1 + W_other = K_2 + U_2 but I'm not sure how so ..

Please help me!
 
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A. The mass of the more massive block can be determined using the equation, K_1 + U_1 + W_other = K_2 + U_2, where K is kinetic energy, U is potential energy and W_other is work done by other forces. We can assume that the total initial potential energy (U_1) is 0. We can also assume that the initial kinetic energy (K_1) is 0. The work done by other forces (W_other) is the same on both sides of the equation, so it cancels out. Therefore, we can rearrange the equation to solve for the mass of the more massive block:Mass = K_2/g*hwhere g is the acceleration due to gravity and h is the height of the more massive block after descending a distance of 1.40 m.Plugging in the given values, we get:Mass = (1.50^2)/(9.8*1.40) = 11.2 kgTherefore, the mass of the more massive block is 11.2 kg.B. The mass of the lighter block can be determined by subtracting the mass of the more massive block (11.2 kg) from the total mass (18.0 kg).Therefore, the mass of the lighter block is 6.8 kg.
 

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