Two cannons, different heights and initial velocities

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Homework Help Overview

The problem involves two cannons firing projectiles horizontally from different heights and with different initial velocities. The original poster questions whether the projectiles can collide if fired simultaneously and if one cannon can delay its shot to ensure a collision.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the conditions for collision, focusing on the equality of x and y coordinates at the time of impact. They explore the implications of the initial heights and velocities of the projectiles.

Discussion Status

Some participants have provided insights into the vertical motion of the projectiles, suggesting that proving the y-coordinates cannot be equal would demonstrate that a collision is impossible. Others have introduced variations of known problems to frame the discussion, indicating a productive exploration of the concepts involved.

Contextual Notes

There is an ongoing examination of the assumptions regarding the initial conditions of the projectiles, including their heights and velocities, as well as the timing of the shots. The discussion also reflects uncertainty about the mathematical relationships governing the motion of the projectiles.

Walter303
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Homework Statement


Two cannons(A at inital height h; B at initial heigt h/2) fire(horizontally), B firing with higher velocity than A.

Homework Equations


1) If they fire at the same time, is it possible that the projectiles collide?
2) Is it possible for B to delay his shot so that his projectile always collides with A's?

The Attempt at a Solution


1) Their x and y coordinates must be the same in case of collision.
xA(t) = xB(t)

x0 + v0A*t = x0 + u*v0A*t
("u" is a positive constant. B's velocity is greater than A's)
v0A = v0B
(but v0A and v0B are different)
I'm not sure about what I should do next...2) I mean, I can get a certain example, but I can't seem to find any formal explanation. For example,
v0A = 10 m/s
v0B = 20 m/s
If B delays the shot by 1 s(tA = 2 s):
v0A*tA = v0B*tB
10*2 = 20*1
then it's possible
 
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Walter303 said:
1) Their x and y coordinates must be the same in case of collision.

Correct. , however if you can prove that the two y co-ordinates can't be the same then you have proved they cannot collide (without needing to think about the x co-ordinates at all). What does the motion in y look like?
 
CWatters said:
Correct. , however if you can prove that the two y co-ordinates can't be the same then you have proved they cannot collide (without needing to think about the x co-ordinates at all). What does the motion in y look like?

They both fire horizontally, so the initial velocity(in y) for both is zero:

h - (1/2)g*t^2 = h/2 - (1/2)*g*t^2

h = h/2

So, it seems that they can't collide. Still, I know there's something wrong here, I just don't know what...
 
This is a variation of the "monkey and the hunter" problem.
If A were aiming at B and B firing level then both bullets would fall the same amount away from the line of fire.
Now, for the second question try
1/2 g tx^2 + g tx * tB + 1/2 g tB^2 = h/2 + 1/2 g tB^2 where tx is the time that bullet A had been falling before bullet B was fired.
This requires both bullets to fall to the same level for collision to occur.
The times involved depend on the separation of the cannons and the speeds of the bullets.
 
" A were aiming at B and B firing level" - I think this should be if "A were aiming at B and B aiming at A"
Then both bullets would fall the same distance from the "line of fire" in time t and would end at the same
height at time t (whatever that is)
 

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