This question has gotten me stuck. I translated it from french to english so pardon that... I just get lost when you include two objects in physics.
A car and a truck move initially in the same direction at 20 m / s, the truck with 38m ahead. The car accelerates at a constant rate of 2m / s ^ 2 exceeds the truck, and falls back into the right lane when it is 11m in front of the truck.
a) How far has the truck traveled in that time?
b) For what value of constant acceleration of the truck it and the car will they have a velocity that differs by only 5 m / s when they intersect? It is assumed that the truck begins to accelerate when a lead of 38m on the car.
d= Vi*t + (0,5)at^2
d= distance of the car
The Attempt at a Solution
But I keep getting negative answers! Someone give me a boost or help me start it! Please!
b) a(car) > 1,67 > s^2