Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a friction

In summary, the final speed of the two carts after colliding head-on is 5.89 m/s. The key to solving this problem is to correctly identify and account for the direction of the initial momenta of the two carts.
  • #1
lettertwelve
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0
[SOLVED] Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a friction

Homework Statement



Two carts with masses of 8.0 kg and 1.8 kg, respectively, move on a frictionless track with velocities of 8.0 m/s and 3.5 m/s. The carts stick together after colliding head-on. Find the final speed.


Homework Equations



m1v1+m2v2 = v (m1 + m2)

v_final = (m1*v1 + m2*v2)/(m1+m2)

The Attempt at a Solution



(8*8)+(1.8*3.5)=70.3
so
70.3=(8+1.8)V
which is then 70.3=9.8V
V=7.17


but it says I'm doing it wrong. (webassign problem)
please show me how i did it wrong?? or what's wrong?
 
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  • #2
You're adding the initial momenta, this is your problem. Define a coordinate system and determine which cart is moving in the positive direction, and which cart is moving in the negative direction (that is, which cart has a positive momentum, which cart has a negative momentum?).
 
  • #3
Everything is perfect...except you forgot one little thing.

Since both Cars are going in opposite directions when they hit each other "head on" (one going left and one is going right), then one of them must be going in the "negative" direction. Let's define "left" as the positive direction:

m1v1-m2v2 = v (m1 + m2)

8(8) - 1.8(3.5) = Vfinal (8+1.8)
57.7=Vfinal (9.8)
Vfinal = 5.89 m/s
 

1. How does the mass of each cart affect the motion of the system?

The mass of each cart affects the motion of the system by determining the amount of force needed to accelerate or decelerate the carts. The larger the mass, the more force is required to change its velocity. In this case, the cart with a mass of 8.0 kg will require more force to move compared to the cart with a mass of 1.8 kg.

2. What role does friction play in the movement of the carts?

Friction is a force that opposes motion, and in this scenario, it acts on both carts. The friction force between the carts and the surface they are moving on will cause them to slow down over time. This means that the carts will eventually come to a stop unless an external force is applied to counteract the friction force.

3. How does the acceleration of the system change if the mass of one cart is increased?

If the mass of one cart is increased, the acceleration of the system will decrease. This is because the total mass of the system has increased, and therefore, more force is needed to accelerate the system. According to Newton's Second Law of Motion, the acceleration of an object is inversely proportional to its mass, meaning that as mass increases, acceleration decreases.

4. Can the carts move at a constant velocity without any external forces acting on them?

No, the carts cannot move at a constant velocity without any external forces acting on them. In the absence of any external forces, the carts will eventually come to a stop due to the friction force acting on them. This is because there is no force to counteract the friction force, and therefore, the carts will continue to slow down until they come to a stop.

5. How does the direction of the net force affect the motion of the carts?

The direction of the net force affects the motion of the carts by determining their overall acceleration. According to Newton's Second Law of Motion, the direction of the acceleration of an object is in the same direction as the net force acting on it. This means that if the net force is in the same direction as the motion of the carts, the carts will accelerate in that direction. If the net force is in the opposite direction, the carts will decelerate.

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