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a home run is hit in such a way that the baseball just clears a wall 21 m high, located 130 m from home plate. The ball is hit at an angle of 35 degrees to the horizontal, and air resistance is negligible.

what's the initial speed of ball?

this is what i did

x=Vxot Vxo=(cos 45)(Vo) and X=130(horizontal distance)

now i try to find t...so i

change in Y=Vy0t - .5g(t^2) so with this i get 21=Sin 45(Yo)t-4.9(t^2)

i simplify that to 20=t(.57v - 4.9t)

i get t=20 or t=.57v/4.9 and i plug the latter into the first equation but i dont get the right answer which is 42 m/s

im thinking that i messed up on my algebra but i don't know.

I would appreciate if someone could help me...thank you