Two-dimensional negative curvature space

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SUMMARY

A two-dimensional space can indeed have constant negative curvature, but it cannot be smoothly isometrically embedded in Euclidean 3-space. This conclusion is derived from the FLRW metric, specifically using the equation $$ds^2=\frac{1}{1-kr^2}dr^2+r^2d\phi^2$$. The Kretschmann scalar, represented as ##R_{ijkl}R^{ijkl}=2k##, confirms that the curvature is constant and can be positive, negative, or zero based on the value of ##k##.

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  • Understanding of two-dimensional geometry
  • Familiarity with the FLRW metric
  • Knowledge of curvature concepts in differential geometry
  • Basic understanding of the Kretschmann scalar
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This discussion is beneficial for mathematicians, physicists, and students of geometry interested in the properties of curved spaces and their implications in theoretical physics.

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TL;DR
Can a two-dimensional space have constant negative curvature?
In this PF Insight says:

(...) if you want a two-dimensional space to be homogeneous and isotropic, there are only three possibilities that fit the bill: space can be uniformly flat, it can have uniform positive curvature, or it can have uniform negative curvature.

Can a two-dimensional space really have constant negative curvature? That is, can a two-dimensional surface with uniform negative curvature be constructed?
 
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Jaime Rudas said:
TL;DR Summary: Can a two-dimensional space have constant negative curvature?

In this PF Insight says:



Can a two-dimensional space really have constant negative curvature? That is, can a two-dimensional surface with uniform negative curvature be constructed?
Yes, but it can’t be smoothly isometrically embedded in Euclidean 3 space.
 
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You can read it off from the FLRW metric with ##dt=d\theta=0##: $$ds^2=\frac{1}{1-kr^2}dr^2+r^2d\phi^2$$Run that through the usual machinery and you get the Kretschmann scalar ##R_{ijkl}R^{ijkl}=2k##, which is obviously everywhere constant positive, negative or zero depending on your choice of ##k##.
 
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