Two lenses problem, multiple interpretations, no true answer

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SUMMARY

The discussion centers on solving a two-lens optical problem involving two lenses with 20 cm focal lengths positioned 1 meter apart. The participant initially used the incorrect equation for lens systems but later identified the simpler lens equation as the appropriate method. The final correct solution for the image location is 28 cm from the right lens, confirmed by the lecturer's solution sheet. Key mistakes included misinterpretation of the object distance and the need to adjust the reference for the new image location.

PREREQUISITES
  • Understanding of the lens formula and its application in optics.
  • Familiarity with the concepts of object distance (u), image distance (v), and focal length (f).
  • Knowledge of refraction indices for different materials (e.g., air and glass).
  • Ability to perform iterative calculations and conversions in optical systems.
NEXT STEPS
  • Study the lens maker's equation for designing optical systems.
  • Learn about ray diagrams for multiple lens systems.
  • Explore the concept of effective focal length in compound lenses.
  • Investigate optical aberrations and their impact on image quality.
USEFUL FOR

Students and professionals in optics, physics educators, and anyone involved in designing or analyzing optical systems using lenses.

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Homework Statement



Two lenses, with 20cm focals are in 1m distance from each other.
A body is located 60cm from the right lens.

Homework Equations


I figured that the relevant equation should be:
[itex]\frac{n1}{u} + \frac{n2}{v} = \frac{n2 - n1}{r}[/itex]
but perhaps a I'm wrong.

The Attempt at a Solution



Using the equation above, when u = 60, n1=1(air), n2=1.5(glass) and r=f*2=40
and then again for u=v' (that we got at the first use of the equation) and my answers vary on my interpretation of the problem - my final answers was 20cm right to the right lense and v=51.42cm to the left of the left lense...
They both were wrong.
 
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I understood my mistakes:
a. the correct equation to use is the simpler lens equation (although we can use the above one, but no need)
b. on the second iteration we need to take the new u from the old v but to do the conversion 100-u=u(new) because the new reference image is between the two lenses.

now the final solution is 28cm (and correct, according to the final solution sheet that our lecturer gave us)
 

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