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Two Long Straight Wires Carrying Curent

  1. Mar 18, 2016 #1

    CARNiVORE

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    Gold Member

    1. The problem statement, all variables and given/known data
    0326c89a8734326470209f09f24d6dea.png

    2. Relevant equations
    B = μ0*i/(2PI*r)

    3. The attempt at a solution
    First of all, if you're looking at this, that means you intend to help me study for my upcoming physics exam on a Friday night. If you fit into this category of people, then god bless your soul.

    I should state that I have all the answers to these, because the solutions are posted - I just want to ensure that I understand the material. Some of the solutions are illegible, but that's not a huge deal.

    So, I understand part a: I use the relevant equation that I typed and replaced 'i' with "i1" and "i2" and replaced 'r' with 'd.' After accounting for unit vectors, the correct answer is:

    B(vector) = μ0*(i1*x(vector) + i2*y(vector))/(2PI*d)

    So, let's start w/ part b: I have no clue what's going on besides that we need to find the force per unit length, which is F3 / L where L is length. The formula sheet equates F3 / L = i3 * B(total). Why is this the case?
     
  2. jcsd
  3. Mar 18, 2016 #2
    so, what is force on a current carrying conductor in a magnetic field?
     
  4. Mar 19, 2016 #3

    CARNiVORE

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    Oops, brain fart - Fm = iL x B, so Fm/L = i3*B(tot). B(tot) is equal to (μ0*√i1^2+i2^2) / (2PI*d), so Fm/L is equal to i3 times this.

    For c, if the angle is to be 45 degrees, then tan^-1(i2/i1) = 45 degrees. This would mean that the ratio of i2/i1 is one to one, so i1 would have to be the same value as i2, which is 40.0 mA. The resultant force vector would be -45 degrees because the force is perpendicular to the B-field.

    I'm confident that these answers are correct. Of course, you can let me know if you see a discrepancy, though. Thanks for your help!
     
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