Two masses m_A and m_B are connected by a string of length l and lie on a frcitionless table. the system is twirled and released with m_A instantatneously at rest, and m_B moving with instantatneously velocity v0at right angles to the line of centres. find the subsequent motion of the system and the tension in the string. in order to find the motion it's easy to use energies: m_Bv0^2/2=m_A*v_A^2/2+m_B*v_B^2/2+I_Aw_A^2/2+I_B*w_B^2/2 where by conservation of angular momentum: we have around the centre of mass of two masses: m_B*v0R_B=m_A*R_A*v_A+m_B*R_B*v_B where v_B=w_B*R_B v_A=w_A*R_A, where the R's are the displacements of the masses from the centre of mass. now to compute the tension i think that T=(m_Av_A^2/R_A)-(m_Bv_B^2/R_B) the problem is that it's obviously not correct, can someone help me in this, thanks.