Two Objects, Constant Acceleration, 1D Forces, Collision Question

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SUMMARY

The discussion revolves around a physics problem involving two objects in one-dimensional motion: a ball dropped from a 50.0 m cliff and a stone thrown upwards at 21.0 m/s. The key equations used include v = v0 + at, x = x0 + v0t + (1/2)at², and v² = v0² + 2a(x - x0). The main challenge is to find the time and height at which the two objects collide, requiring the establishment of equal time and height conditions for both objects. The user expresses difficulty in solving the quadratic equation derived from setting the motion equations equal to each other.

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Homework Statement



A ball is dropped from the top of a 50.0 rm m-high cliff. At the same time, a carefully aimed stone is thrown straight up from the bottom of the cliff with a speed of 21.0 m/s. The stone and ball collide part way up.

Homework Equations



v = v0+at
x = x0 + v0t + (1/2)at2
v2 = v20+2a(x- x0)

The Attempt at a Solution



Two objects, each with different components of one-dimensional motion. The two objects will share a common impact time because they are put into motion at the same time. I have tried solving for time and setting the equations equal to each other, but this yields no result because when I arrange the quadratic formula it evaluates to y = 0, which doesn't make sense. I don't need explicit help (although I don't mind, I just hate typing this out so I don't expect people trying to help me to), I just need a direction to take this problem.

Thanks
 
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What is the question?
 
If they collide there are two things that must be equal.

Time. and Height.
 

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