Two resistors connected to a battery

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Homework Statement
In a circuit, a 100.-ohm resistor and a 200.-ohm resistor are connected in parallel to a 10.0-volt battery.

Determine the power dissipated by the 100.-ohm resistor.

Calculate the current in the 200.-ohm resistor.
Relevant Equations
P=VI
P=I^2R
P= V^2/R
I honestly have no idea how to do this problem whatsoever. My teacher didn't show an example like this before.
 
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jay_buckets said:
Homework Statement:: In a circuit, a 100.-ohm resistor and a 200.-ohm resistor are connected in parallel to a 10.0-volt battery.

Determine the power dissipated by the 100.-ohm resistor.

Calculate the current in the 200.-ohm resistor.
Relevant Equations:: P=VI
P=I^2R
P= V^2/R

I honestly have no idea how to do this problem whatsoever. My teacher didn't show an example like this before.
Welcome to the PF.

When the two resistors are connected in parallel to the battery, you can treat them as independent. Does that help? You have written the correct equations -- try applying them to the first question and show your work please. Thank you.
 
P= (10v^2)/(200.ohm) = 0.5 W. is that the correct answer for part 1?
 
jay_buckets said:
P= (10v^2)/(200.ohm) = 0.5 W. is that the correct answer for part 1?
I think part 1 asks about the 100 Ohm resistor, no? And good start, BTW. :smile:
 
ohhhh yeah it does oops. So would it be 1 W then?
 
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would you use 1W=(I^2)100 ohms and then 1W/100ohms= I^2?
 
wait no would you calculate the power dissipated by the 200 ohm resistor and then use that formula?
 
oh yeahhh thank you for your help!
 
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You're welcome. And for bonus points, can you answer the same two questions for the case where the two resistors are connected in series across the 10 Ohm Volt battery? Hint -- start by calculating the series current by using the total series resistance and the battery voltage... :smile:
 
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