- #1
ImpCat
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Homework Statement
Homework Equations
R=V/I
The Attempt at a Solution
Would it be 10ohms? Since PQ is between two 10ohms resistor.
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Are the two resistors in parallel or series or some other configuration?ImpCat said:Homework Statement
View attachment 109814
Homework Equations
R=V/I
The Attempt at a Solution
Would it be 10ohms? Since PQ is between two 10ohms resistor.
berkeman said:Are the two resistors in parallel or series or some other configuration?
Hint -- what do parallel resistors share?
CWatters said:Try colouring all wires connected to "P" one colour and all wires connected to "Q" another colour.
What does your textbook or course notes say about how resistors combine to create a net resistance?ImpCat said:But how would I know the resistance just from the resistance of the other two resistors?
gneill said:What does your textbook or course notes say about how resistors combine to create a net resistance?
How do you justify that? Can you explain your reasoning?ImpCat said:So the net resistance in this circuit would be rTotal= r1+ 1/(1/r1 +1/r2)
gneill said:How do you justify that? Can you explain your reasoning?
Very good. So in the end, are these two resistors in series or parallel? What is your final answer?ImpCat said:As in a series, the total resistances are simply added up, and in parallel, the resistances are added up by 1/r1 +1/r2 = 1/rTotal. So if I added up the parallel resistors and pretend it is just 1 resistor with a resistance of 1/(1/r1 +1/r2)=rX, then the total resistance in the circuit would be rX+r1(Where r1 is the 10ohms resistor in the series)=rTotal.
berkeman said:Very good. So in the end, are these two resistors in series or parallel? What is your final answer?
No.ImpCat said:So if I added up the parallel resistors and pretend it is just 1 resistor with a resistance of 1/(1/r1 +1/r2)=rX, then the total resistance in the circuit would be rX+r1(Where r1 is the 10ohms resistor in the series)=rTotal.
NascentOxygen said:No.
Once you have accounted for a resistor, you can't then include it in a second accounting.
Has anyone told you to redraw the circuit, using as many trials as is necessary, until you can draw them unequivocally as a pair of resistors in either (a) a series arrangement, or (b) a parallel arangement. It must be one or the other.
I have no idea what all that is about.ImpCat said:Actually, I used v1 both times as the two resistors provided are of the same ohms, and I was too lazy to change its symbol. So you can treat one of the v1 as vb or vy. Sorry for the confusing equations xD. Also, I did convert the circuit into a series, by adding the parallel resistors together and treat it as a series along with the 10ohms resistor.
NascentOxygen said:I have no idea what all that is about.
►► So, is your answer to the question that started this thread now A, B, C or D?
Why do you keep referring to 3 resistors when there are only 2?ImpCat said:I tried totaling the resistance on the parallel resistors (Rtotal) and treat it as a series with the 10ohms resistor.
NascentOxygen said:Why do you keep referring to 3 resistors when there are only 2?
Once you have worked out the equivalent resistance of the pair of resistors, then STOP! That is your answer! There is nothing more to be done!
ImpCat said:the resistance on the parallel resistors
ImpCat said:the known resistors are in a series
NascentOxygen said:You have not yet determined whether the two resistors are in a parallel arrangement, or are in series?
How would you recognize a parallel arrangement? How would you recognize a series arrangement?
You probably do know, but that is not a clear enough answer to earn any marks in an exam.ImpCat said:A series arrangement would be where the resistors are connected next to each other. Parallel would be where the path of the resistors are divided.
There are no unknown resistors here. There are two known resistors, they are known to be 10Ω each. There are no more resistors; there are just two resistors. There are not 3 resistors, and not 4 resistors. Just two!So the unknown resistor and 1 of the known resistor are in parallel. There is also one known resistor of 10ohms that are in series to the parallel resistors. Right?
NascentOxygen said:You probably do know, but that is not a clear enough answer to earn any marks in an exam.
There are no unknown resistors here. There are two known resistors, they are known to be 10Ω each. There are no more resistors; there are just two resistors.
NascentOxygen said:There is no additional unshown resistance between P and Q, though it wouldn't make any difference if there were. All we are interested in doing in this exercise is replacing what you can see with its equivalent.
Nidum said:Perhaps this picture will help you understand the problem more clearly . It just shows the same circuit drawn in different ways .
ATTACH=full 109845[/ATTACH]
And to confirm to an examiner that B is not just a guess, how do you justify giving that as the answer?ImpCat said:I see now, thanks for your help! The answer would then be B.
NascentOxygen said:And to confirm to an examiner that B is not just a guess, how do you justify giving that as the answer?
Well, an examiner could ask how did you recognize it to be a parallel arrangement, and not a series arrangement of two 10 Ω resistors?ImpCat said:By treating it as a parallel circuit so 1/10 + 1/10 = 1/r
r=5
NascentOxygen said:Well, an examiner could ask how did you recognize it to be a parallel arrangement, and not a series arrangement of two 10 Ω resistors?
Resistance is the measure of the opposition to the flow of electric current through a material. It is denoted by the symbol "R" and is measured in units of ohms (Ω).
Resistance is calculated using Ohm's Law, which states that resistance is equal to the voltage (V) divided by the current (I). This can be expressed as R = V/I.
The resistance between two resistors is affected by the type of material they are made of, their length, cross-sectional area, and temperature. The longer and thinner the resistor, the higher the resistance. Additionally, as temperature increases, resistance also increases.
No, resistance cannot be negative. It is always a positive value as it represents the opposition to the flow of electric current.
The higher the resistance between two resistors, the lower the flow of electric current. This is because the resistance acts as a barrier to the flow of electrons, impeding the current. Conversely, lower resistance allows for a higher flow of current.