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I'm using a U-Shaped Ferrite Core with coils in both legs of the U.

I've calculated it's inductance using an analogy between electric/magnetic circuits.

L = N

where:

N = number of turns of coil in both legs of the U;

R

R

R

R

R

I get a value of

When I plug it to a LCR meter , with a current of 19,91 mA the inductance

Can someone tell me how I can relate both inductances?

Thanks in advance[/SUB]

I've calculated it's inductance using an analogy between electric/magnetic circuits.

L = N

^{2}/R_{total}where:

N = number of turns of coil in both legs of the U;

R

_{total}is the total reluctance of my circuit = R_{1}+ R_{2}R

_{1}= l_{1}/μ0*μ_{r,core}*AR

_{2}= l_{2}/μ0*μ_{r,air}*AR

_{1}is the reluctance of the circuit within the Ferrite core, where l_{1}is the mean lenght of the circuit (=0,189m), μ_{r,core}is the relative permeability of the core (≈1000) and A is the cross-sectional area (=7e-4 m^{2}).R

_{2}is the reluctance of the air gap between both legs of the Ferrite core, where l_{2}is the mean lenght of the magnetic circuit (=0,093m), μ_{r,air}. =1, and the A is the same as in R_{1}.I get a value of

**L =1,51 mH**for a total of 400 turns of coil (N=400).When I plug it to a LCR meter , with a current of 19,91 mA the inductance

**L equals 14,21 mH**.Can someone tell me how I can relate both inductances?

Thanks in advance[/SUB]

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