# UAM & Electrostatics: Does It Apply At Atomic Scale?

• metalmagik
In summary, the UAM equations can be used to calculate the final velocity of a proton when given its initial velocity, electric field magnitude, and distance.
metalmagik
Do UAM equations apply on an atomic scale when dealing with protons and electrons etc?

metalmagik said:
Do UAM equations apply on an atomic scale when dealing with protons and electrons etc?
You mean the The Urban Airshed Model - UAM-IV?

http://www.ccl.rutgers.edu/~ssi/thesis/thesis-node56.html

Or maybe you are talking about uniformly accelerated motion?

The classical notions of particle motion do not hold up on the atomic scale. The theory of quantum mechanics is used to analayze such problems.

Last edited by a moderator:
I am talking about Uniformly Accelerated Motion. hm, I see they cannot be used. How do I then find a final velocity for a proton when I am given the initial velocity, electric field magnitude, and distance?

metalmagik said:
I am talking about Uniformly Accelerated Motion. hm, I see they cannot be used. How do I then find a final velocity for a proton when I am given the initial velocity, electric field magnitude, and distance?
They can be used. See the other thread where the context of your problem is stated. You need to change your understanding of what atomic scale means. It is not about the size of the particle. It is about the distances involved in the motion.

I see, I understand this now, thank you very much.

If you're still around. Here is my work for the problem I was confused about using UAM equations with:

A uniform electric field has a magnitude of 3.0 x 10^3 N/C. In a vacuum, a proton begins with a speed of 2.4 x 10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of 1.0 mm.

$$F = qE$$

$$F=(1.6 x 10^-19)(3 x 10^3)$$

$$F = 4.8 x 10^-16 N$$

$$F = ma$$

$$4.8 x 10^-16 N = (1.67 x 10^-27 kg) a$$

$$a = 2.87 x 10^(11) m/s^2$$

$$Vf^2 = Vi^2 + 2ad$$

$$Vf^2 = (2.4 x 10^4)^2 + 2(2.87 x 10^11)(.001)$$

$$Vf = 3.39 x 10^4 m/s$$

eh some of the exponents in the latex got skewed, but I am sure you can figure it out. If you can verify this answer for me, that'd be great.

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metalmagik said:
If you can verify this answer for me, that'd be great.
Looks OK . . . .

## What is UAM and electrostatics?

UAM (Ultrafast Atomic Force Microscopy) is a technique used to study the structure and properties of materials at the atomic scale. Electrostatics is the study of electric charges at rest and their interactions.

## How does UAM and electrostatics apply at the atomic scale?

UAM and electrostatics apply at the atomic scale because they both involve interactions between individual atoms and their electric charges. UAM allows us to visualize the atomic structure and electrostatic forces at work on a surface, while electrostatics helps us understand the behavior of electric charges on a smaller scale.

## What are some potential applications of UAM and electrostatics at the atomic scale?

UAM and electrostatics have a wide range of potential applications, including studying the behavior of molecules and materials, investigating surface properties and interactions, and developing new technologies such as nanoelectronics and nanophotonics.

## How accurate is UAM and electrostatics at the atomic scale?

UAM and electrostatics are highly accurate at the atomic scale, as they allow us to directly observe and measure the properties and interactions of individual atoms. However, the accuracy also depends on the specific techniques and instruments used, as well as the skill and experience of the researcher.

## What are the limitations of using UAM and electrostatics at the atomic scale?

One limitation of UAM at the atomic scale is the difficulty in controlling and manipulating individual atoms and their charges. Additionally, electrostatics may not accurately account for quantum effects and other factors that can influence atomic behavior. Furthermore, the resolution of UAM and electrostatics may be limited by the size of the probes or the noise in the measurements.

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