Ugly first order differential equation

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SUMMARY

The forum discussion focuses on solving the first-order differential equation (1+t²)y' + 4ty = (1+t²)⁻². The integrating factor μ is derived using the formula μ = exp(∫a dt), where a = 4t/(1+t²). The correct integrating factor is μ = e^(2ln(1+t²)) = (1+t²)², which simplifies the equation for easier integration. Participants clarify the steps to manipulate the equation and apply the product rule effectively.

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cameuth
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Homework Statement


solve the differential equation:
(1+t^2)y'+4ty=(1+t^2)^-2

Homework Equations



μ=exp∫adt

The Attempt at a Solution


this problem gets quite ugly, so here goes.
first question
does μ=e^(1+t^2)^2
 
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I don't think the integrating factor is as bad as you think.
write the equation as [itex]y'+ \frac{4ty}{1+t^2}= \frac{1}{(1+t^2)^3}[/itex]
now what do I need to multiply this equation through to run the product rule backwards on the left hand side.
 
cameuth said:
μ=e^(1+t^2)^2
Nope. How did you get that?
 

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