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Ugly first order differential equation

  1. Feb 5, 2012 #1
    1. The problem statement, all variables and given/known data
    solve the differential equation:
    (1+t^2)y'+4ty=(1+t^2)^-2


    2. Relevant equations

    μ=exp∫adt

    3. The attempt at a solution
    this problem gets quite ugly, so here goes.
    first question
    does μ=e^(1+t^2)^2
     
    Last edited by a moderator: Feb 6, 2012
  2. jcsd
  3. Feb 6, 2012 #2
    I don't think the integrating factor is as bad as you think.
    write the equation as [itex] y'+ \frac{4ty}{1+t^2}= \frac{1}{(1+t^2)^3} [/itex]
    now what do I need to multiply this equation through to run the product rule backwards on the left hand side.
     
  4. Feb 6, 2012 #3

    vela

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    Nope. How did you get that?
     
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