Ugly trig and exponential problem

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    Exponential Trig
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Homework Help Overview

The discussion revolves around the analysis of a trigonometric and exponential equation: 8*sin(t) - 16*cos(t) = 9*exp(-t/2). Participants explore various algebraic methods to analyze the equation rather than relying on graphical solutions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss attempts to convert the exponential part into a Fourier series and express sine and cosine in terms of exponential functions. There are questions about the applicability of these methods given the complexity of the equation.

Discussion Status

Some participants express skepticism about finding an algebraic solution, suggesting a shift towards graphical methods. Others inquire about the feasibility of certain transformations and the implications of complex numbers in their approaches.

Contextual Notes

There is mention of the challenges posed by the non-linear nature of the equation and the difficulty in defining an integrable period for the Fourier series. Participants also note the constraints of their methods, particularly regarding the constants in the Taylor series expansion.

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Homework Statement


This isn't a problem, I'm just obsessed with analyzing a trig/exp equation algebraically instead of with a calculator.

8*sin(t) - 16*cos(t) = 9*exp(-t/2)


Homework Equations



See part (1.) above...


The Attempt at a Solution



I tried converting the exp part into a Fourier series; if you graph the equation, this method recommends itself due to the multiple solutions. I didn't have much success with this method, though, since the first term in the Fourier series contains two exp terms. In addition, the Fourier series requires the definition of an integrable "period", and I wouldn't know what to do for that.

I also tried converting the sine and cosine terms into exp terms with complex arguments, but then I've got imaginary numbers all over the place, and I already know the answer isn't complex from the solution obtained by calculator, which was verified graphically.

Any recommendations would be grand.
 
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gulfcoastfella said:

Homework Statement


This isn't a problem, I'm just obsessed with analyzing a trig/exp equation algebraically instead of with a calculator.

8*sin(t) - 16*cos(t) = 9*exp(-t/2)


Homework Equations



See part (1.) above...


The Attempt at a Solution



I tried converting the exp part into a Fourier series; if you graph the equation, this method recommends itself due to the multiple solutions. I didn't have much success with this method, though, since the first term in the Fourier series contains two exp terms. In addition, the Fourier series requires the definition of an integrable "period", and I wouldn't know what to do for that.

I also tried converting the sine and cosine terms into exp terms with complex arguments, but then I've got imaginary numbers all over the place, and I already know the answer isn't complex from the solution obtained by calculator, which was verified graphically.

Any recommendations would be grand.

I forgot to mention another method I attempted...
I converted both sides of the equation (the trig side and the exp side) to Taylor series. The terms line up beautifully, but the constants multiplied on each term in the original equation throw the equations out of whack.
 
I've decided that this equation is so far past non-linear that it can't be solved algebraically. I'm going to go with the graphical intersection method, and let the problem go.
 
Did you try writing sin(x) as [itex](e^{ix}- e^{-ix})/(2i)[/itex] and cos(x) as [itex](e^{ix}+ e^{-ix})/2[/itex] so everything is in terms of the exponential?
 
HallsofIvy said:
Did you try writing sin(x) as [itex](e^{ix}- e^{-ix})/(2i)[/itex] and cos(x) as [itex](e^{ix}+ e^{-ix})/2[/itex] so everything is in terms of the exponential?

I tried that, but couldn't figure out where to go with it.
 
There is no algebraic solution to this.
 
Avodyne said:
There is no algebraic solution to this.

As I suspected... is there a reason or proof or reference that you can link me to?

Thanks.
 

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