Uncertainty on the number of trials in binomial distributions?

AI Thread Summary
The discussion centers on calculating uncertainty in the number of trials for a binomial distribution. The original poster seeks clarification on how to determine the uncertainty when tossing a coin 100 times, specifically asking for the error margin. It is clarified that the uncertainty lies in the outcomes (heads or tails), not the number of trials. For 100 coin tosses resulting in 50 heads, the standard deviation is calculated to be 5, leading to a result of 50 heads ± 5. Understanding this concept is crucial for accurately interpreting results in binomial distributions.
penguindecay
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Dear Reader,

I am writing for information, or a point towards any information about the calculation on the uncertainty on the number of trials in a binomial distribution. I had been using the SQRT(N) (taken from poisson dist. I miss them) but forgot they are binomial. For example if I toss a coin 100 times, (lands 50 heads 50 tails), what would the uncertainty/error be on that 100 trials? That is to say 100 +/- ?. Thank you for your help,

Kim
 
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The description you give has the number of trials as given (no uncertainty). The uncertainty would be in the number of heads or number of tails. One standard deviation in this case is 5, so you would say the number of heads would be 50 +/- 5.
 
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