Uncertainty Principle and the lifetime of an excited state

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SUMMARY

The discussion focuses on estimating the lifetime of an excited state of an atom with a natural emission line width of 3.00 × 10−4 eV using the uncertainty principle. The relevant equations are ΔEΔt = h/(2π) and ΔEΔt = (1/2)h/(2π). The consensus is that the second equation provides the correct estimate for Δt when substituting ΔE. While the first equation is considered a more accurate version, both yield approximate estimates, and instructors are likely to accept either approach.

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Homework Statement


[/B]
Estimate the lifetime of the excited state of an atom whose natural emission line width is 3.00 × 10−4 eV.

Homework Equations



$$ \Delta E \Delta t = \frac{1}{2} \times \frac{h}{2\pi} $$
$$ \Delta E \Delta t = \frac{h}{2\pi} $$

The Attempt at a Solution



I think all I have to do is rearrange for Δt then sub in the energy given as ΔE, but I'm not sure when I use which equation above, the correct answer is using the second, but I thought the first equation was a more accurate improved version of the second?
 
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Wikipedia favors the first of your two equations where delta is the standard deviation of the quantity. Using either formula, you only get an approximate estimate. I think most instructors would accept either answer.
 
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