Uncharged object between two charged plates

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When an uncharged object is placed near a positively charged plate, the electrons in the object are attracted to the positive plate while the protons are repelled. This creates a polarization effect, where the electrons shift towards the positive plate, but the overall force from the negative plate is weaker due to increased distance. The discussion highlights the difference between the electric fields of charged plates and charged spheres, emphasizing that the forces acting on the uncharged object are balanced. Ultimately, the conclusion drawn is that the uncharged object does not move because the opposing forces from the two plates cancel each other out. Understanding these interactions is crucial for grasping the behavior of charged and uncharged objects in electric fields.
Biker
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Homework Statement


Imagine if you have two charged plates which have the same magnitude but opposite in charges.
If you place an uncharged object near of the positive plate what will happen?

Homework Equations


I don't think it depends on equations

The Attempt at a Solution


Okay, so If you rub a balloon with your hair, it will gain a negative charge. If you place that balloon really close to really small pieces of paper, It will attract them because the balloon will repel the electrons away from it and the protons don't move so the object will be polarized ( I am pretty sure that I can't say that this effect split the electrons and protons into two different sides equally , can I?)
So the negative charge will attract the protons more than it will attract the electrons because the protons are much closer to it than the electrons. So that will result in a net force to the balloon.

Now back to the question
If I place the uncharged object near the positive plate, the opposite of the above will happen. However, The negative charged plate will attract the protons and the positive plate will repel the protons in the same direction
and the same thing will happen to the electrons but opposite.

The answer in my book was that the uncharged object won't move. But what I think if we assume that it won't move we are just saying that the (distance) between the repelled electrons and attracted protons is just zero which proves that the first idea is wrong.So, What is really happening here?

Thanks in advance.
-Biker
 
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There's a difference between the field from a charged sphere and the field between parallel plates. As you say, the electrons in the object will be attracted towards the positive plate, but what does that mean regarding the interaction with the negative plate?
 
haruspex said:
There's a difference between the field from a charged sphere and the field between parallel plates. As you say, the electrons in the object will be attracted towards the positive plate, but what does that mean regarding the interaction with the negative plate?
Sorry, I didn't get your question. Could you explain what you mean?

The positive plate will attract electrons and the negative plate will repel electrons, But also I have to take into account that the positive plate will repel protons and the negative plate will also attract protons. If that is what you mean

The force of the negative plate will be weaker (because it increases the distance) than the force of the positive plate but they are in the same direction
 
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Biker said:
The force of the negative plate will be weaker (because it increases the distance) than the force of the positive plate but they are in the same direction
If the plates are parallel and close to each other, the electric field is homogeneous between them.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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