Understanding a step in a Biot-Savart law problem

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SUMMARY

The discussion centers on the application of the Biot-Savart law, specifically addressing the cross product of vectors dl and r. The authors of the referenced book express the cross product as dl sin(π/2 - θ) rather than dl sin(θ) because the angle between the vectors is indeed (π/2 - θ). This clarification resolves the confusion regarding the sine function's argument in the context of the cross product formula.

PREREQUISITES
  • Understanding of vector mathematics and cross products
  • Familiarity with the Biot-Savart law in electromagnetism
  • Basic knowledge of trigonometric functions and their properties
  • Ability to interpret diagrams related to vector angles
NEXT STEPS
  • Study the derivation and applications of the Biot-Savart law
  • Learn about vector cross product properties and their geometric interpretations
  • Explore trigonometric identities, particularly those involving sine and cosine
  • Review examples of electromagnetic field calculations using the Biot-Savart law
USEFUL FOR

Students and professionals in physics, particularly those studying electromagnetism, as well as educators seeking to clarify vector operations in the context of the Biot-Savart law.

Anti Hydrogen
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Homework Statement
Biot-Savart law
Relevant Equations
Biot-Savart law
I can't understand intuitively why the authors of the book expressed the cross product between the vectors dl and r (unit vector) as: dl sin(pi/2 - theta); isn't it supposed to be expressed as: dl sin(theta)?? So why did the authors put that pi/2 into the argument of sin function, that's my question, please check the file I attached
 

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Anti Hydrogen said:
Homework Statement:: Biot-Savart law
Relevant Equations:: Biot-Savart law

I can't understand intuitively why the authors of the book expressed the cross product between the vectors dl and r (unit vector) as: dl sin(pi/2 - theta); isn't it supposed to be expressed as: dl sin(theta)?? So why did the authors put that pi/2 into the argument of sin function, that's my question, please check the file I attached
In the cross product formula it is sin(angle between the vectors). In the diagram, the angle between the vectors is (π/2-θ).
 
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haruspex said:
In the cross product formula it is sin(angle between the vectors). In the diagram, the angle between the vectors is (π/2-θ).
That makes sense!; I can't believe I didn't consider that! Thanks!
 

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