Understanding a Thermo Diffusion Equation Problem: A Comparison of Solutions

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Homework Help Overview

The discussion revolves around a thermo diffusion equation problem involving boundary conditions and the solution of a second-order ordinary differential equation (ODE). The original poster presents an equation and their attempt at solving it, which differs from the solution provided in their textbook.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve the ODE but questions the validity of their solution compared to the textbook. Participants suggest examining boundary conditions and the inclusion of terms in the solution. There is a focus on understanding how to derive the correct expression for T(L) and its implications for the overall solution.

Discussion Status

Participants are actively engaging with the problem, providing insights into the original poster's approach and suggesting corrections. There is a recognition of the need to incorporate boundary conditions properly, and some participants have identified steps that may lead to the textbook solution.

Contextual Notes

The discussion highlights potential misunderstandings regarding boundary conditions and the derivation of terms in the solution. The original poster expresses confusion about specific components of the solution, particularly the term '(k+h*L)'.

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im given the equation:

k d[tex]^{2}[/tex]T/dx[tex]^{2}[/tex] = 0 over 0 < x < L = 0.4

with T(0)=T and -k dT(L)/dx = h(T(L)-Tinf)



i tried to solve it and i got

T(x) = (-h(T(L)-Tinf)x)*(1/k)

the book gives

T(x) = ( (k+h(L-x))T+h*x*Tinf)*(1/ (k+h*L) )

i don't understand what went wrong... help!
 
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If you plug x = 0 into your expression, you'll find you get T(0) = 0, which is not the boundary condition you're given. You want T(0) = T.

Solving the ODE gives you T(x) = Ax + B. In your solution you appear to have dropped the B term and only solved for A. Keeping B and solving for it should fix the problem.
 
thanks i don't know why that happened. that just adds a +T after my original solution. i still don't understand where they got the '(k+h*L)' from...
 
Okay, I see what the other step they did is. Your condition on the derivate of T is defined in terms of T(L), so you get as your solution

[tex]T(x) = -\frac{h}{k}(T(L) - T_{\infty})x + T[/tex]

So, at x = L, you have

[tex]T(L) = -\frac{h}{k}(T(L) - T_{\infty})L + T[/tex]

so you need to solve for T(L). Plugging that back into your original expression should (hopefully) get you the book's solution.
 

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