touqra
- 284
- 0
The Ampere's Law is \nabla \times B = \mu J and Gauss's Law is \nabla \cdot E = \frac{1}{\epsilon} \rho
Since J is current density, is it right to say that, J = \frac{d}{dt} \rho in general?
I am abit confused, since I know that a current four-vector, (\rho , J) is similar to a spacetime four-vector (t, x). But, x is not \frac{d}{dt} t
Also, does a non-zero J automatically implies a non-zero \rho ?
Since J is current density, is it right to say that, J = \frac{d}{dt} \rho in general?
I am abit confused, since I know that a current four-vector, (\rho , J) is similar to a spacetime four-vector (t, x). But, x is not \frac{d}{dt} t
Also, does a non-zero J automatically implies a non-zero \rho ?