Understanding Big O Notation: Limit Definition and Reconciling Statements

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Discussion Overview

The discussion revolves around the interpretation of Big O notation in the context of a mathematical statement involving norms and epsilon. Participants explore the relationship between the limit definition of Big O and specific inequalities presented in a finite element theory context, questioning the dependence of certain variables on epsilon.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant questions the statement "||u||<=eps*||f|| means ||u||=O(eps)", suggesting that it is unclear how ||u|| depends on epsilon.
  • Another participant points out a potential typo in the relation, proposing that it should be "u=O(f)" instead of "||u||=O(eps)".
  • A participant provides context from a finite element theory book, indicating that ||u-u_s|| is of order eps^2 while ||u-u_s||_E is of order eps.
  • There is a suggestion that the author may not be using standard Big O notation, and a request for citation is made.
  • One participant proposes that the inequalities imply ||u-u_s||/||f||<=eps indicates that ||u-u_s|| is "of order epsilon".
  • Another participant discusses the possibility of expanding expressions involving epsilon, questioning the meaning of epsilon in the context provided.

Areas of Agreement / Disagreement

Participants express differing interpretations of the statements regarding Big O notation and its application to the given inequalities. There is no consensus on the correct interpretation or the author's intent.

Contextual Notes

Participants highlight the need for clarity regarding the definitions and assumptions related to the norms and the variable epsilon, as well as the context in which these statements are made.

ericm1234
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I am trying to reconcile the following statement:

" ||u||<=eps*||f|| means ||u||=O(eps) ("||u|| is order eps")... "

with the limit definition of "big O"; considering it's not clear that ||u|| here even depends on eps:

" lim as eps goes to 0 of ||u||/eps, by definition of "big O", should equal some constant "; is it necessarily ||f||?

I understand that, for example, sin(x)=O(x) because lim as x goes to 0 of sin(x)/x is bounded.

So to casually say something is "order epsilon", if it doesn't depend on epsilon, I am not sure how to reconcile that with the definition of "big O" given by the limit one should be able to take, as above.
 
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I paraphrased for the sake of drawing attention to my (pedantic) question;
The original statement, from a book on finite element, was:
||u-u_s||<=eps*||u-u_s||_E <=eps^2*||f|| (the middle norm is energy norm)

the following text then goes:
"The point of course is that ||u-u_s||_E (energy norm) is of order eps, whereas ||u-u_s|| is of order eps^2."

So maybe you can explain based on this context then?

And sorry for lack of "tex" skills.
 
It looks like the author is not using regular big-O notation and/or conventions here.
Please provide a citation.

Possibly the author just refers to the order in "epsilon".
What is epsilon supposed to stand for?
 
Last edited:
Well, that was sort of what I figured..but anyway, Brenner, Mathematical Theory of Finite Element, p.6 bottom.

Thanks
 
I don't know that one - the best way to be sure is to look for the same lesson in another text and compare.

If I said that |y| = x|k| while |z|=x^2|k| then you could say that y = O(x) while z=O(x^2).
I'm thinking that the dependent variable in the inequalities above is epsilon.
 
Thanks; do you believe (as in, is it plausible) that the author means: ||u-u_s||/||f||<=eps means that thing less than eps is "of order epsilon"?
 
Really need the context.
But, especially if ||f|| is just a number, it would be fair to say that ||u-u_s||=O(eps)
i.e. it seems one could expand the expressions as ##\sum_n a_n\epsilon^n ## ... whatever epsilon is supposed to represent. You are the one with the book in front of you.
 

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