Understanding Charge Transfer in C & 2C Circuit

[arpon]

Homework Statement

[/B]
C and 2C represent the capacitance of the respective capacitors. L and 2L represent the inductance of the respective inductors. Let, the charge on the capacitors GM and PM be q_1 and q_2 which are variable. t represents time. Initially (when the switch k was closed and t = 0) , q_1 = \frac{2q_0}{3} ; q_2 = \frac{q_0}{3}. Would it be,
i_1 = - \frac{dq_1}{dt} ; i_2 = - \frac{dq_2}{dt} ?
Explain your answer.

Homework Equations

That is conceptual question. No equation is needed.

The Attempt at a Solution

The actual homework was different. But I need to clear my concept before solving the actual problem. My confusion is, the MGHJ segment (which has the current i_1) is connected with both the capacitors. So, won't both the capacitor affect the current i_1 ?

 

[gneill]

The short circuit between M and J when the switch is closed effectively creates two isolated loops as no potential can develop across the short. In other words, M and J become a single node. No current from either loop can stray into the other loop past that short circuit.

 

[arpon]

The short circuit between M and J when the switch is closed effectively creates two isolated loops as no potential can develop across the short. In other words, M and J become a single node. No current from either loop can stray into the other loop past that short circuit.

So, if I change the circuit into the following , I think i_1 and i_2 won't change. Am I right?

 

[gneill]

Right.