Understanding Contour Integrals: A Brief Introduction

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Contour integrals involve integrating a function along a one-dimensional curve, parameterized by a variable like t. The integral can be expressed by rewriting the function in terms of this parameter, allowing for the evaluation of the integral along a specified path. An example provided illustrates integrating a function over a great circle on a sphere, detailing the parameterization and the resulting integral expression. The discussion emphasizes the need for a clear definition and formula for contour integrals, which can often be found in textbooks. Understanding this concept is essential for applying contour integrals in various mathematical contexts.
Keru
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Hi there! I'm almost sure that somebody has previously make this same question so, if it is like that, I'm sorry.
I've just been introduced to contour integrals, I've tried to look around the internet and some textbooks, but i can't find out what do they actually are so, if someone could explicitly explain me what is exactly a "contour integral", i'd be very grateful.

PD: By explicitly I mean the formula for doing that integral, there're many examples around the internet, but i haven't found a general expression that explains how to do them...

Anticipated thanks :)
 
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The definition of the contour integral, which should be included in your textbook, is pretty much all you need:
A contour is a one-dimensional curve so x, y, and z can be written in terms of a single parameter, t, say. Then write the function to be integrated in terms of that parameter.

For example, to integrate x^2dx+ xydy+ z dz from (1, 0, 0) to (-1, 0, 0) along the great circle, above the xy-plane, on the sphere x^2+ y^2+ z^2= 1, we can write x= cos(\theta), y= 0, z= sin(\theta). Then dx= -sin(\theta)d\theta, dy= 0, and dz= cos(\theta)d\theta.

So x^2dx= (cos^2(\theta)(-sin(\theta)d\theta)= -cos^2(\theta)sin(\theta)d\theta, xydy= 0, and zdz= (sin(\theta))(cos(\theta d\theta)= sin(\theta)cos(\theta)d\theta.<br /> <br /> We go from (1, 0, 0) to (-1, 0, 0) by taking \theta from 0 to \pi. The integral becomes<br /> \int_0^\pi (-cos^2(\theta)sin(\theta)+ sin(\theta)cos(\theta)d\theta= \int_0^\pi (cos(\theta)- cos^2(\theta))sin(\theta)d\theta
 
Ok, it's been a little hard to follow since i can't see the symbols correctly, but i finally got it, ty a lot :)
 

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