Understanding cot2(theta) = A-C / B

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SUMMARY

The discussion centers on the transformation of the equation A'x'^2 + B'x'y' + C'y'^2 + D'x' + E'y' + F = 0 into the form B' = 2(C-A)sin(theta)cos(theta) + B(cos^2(theta) - sin^2(theta)). Participants clarify that this transformation is not a deduction but rather a definition of the new coefficient B', which represents the coefficient of x'y'. The key to obtaining the new equation lies in expanding the original equation and collecting terms based on the powers of x' and y'. The discussion emphasizes the importance of tracking terms and simplifying to derive the desired result.

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Terrell
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Homework Statement


How did it go from A'x'^2 + B'x'y' + C'y'^2 + D'x' +E'y' + F = 0 to become B' = 2(C-A)sin(theta)cos(theta) + B(cos^2(theta) - sin^2(theta))?

*this is not an assignment, I am just self studying :P
 

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Expand the top most equation then collect the terms based on the powers of ##x'## and ##y'##. To obtain (12), just keep track on the terms in the top most equation which contain ##x'y'##.
 
Terrell said:

Homework Statement


How did it go from A'x'^2 + Bx'y' + C'y'^2 + D'x' +E'y' + F = 0 to become B' = 2(C-A)sin(theta)cos(theta) + B(cos^2(theta) - sin^2(theta))?
The latter is not a deduction from the former. It is simply a definition, which the author is free to make, as the symbol B' has not been used up to that point.

The deduction is the equation immediately after the 'where...' part.
 
blue_leaf77 said:
Expand the top most equation then collect the terms based on the powers of ##x'## and ##y'##. To obtain (12), just keep track on the terms in the top most equation which contain ##x'y'##.
yes. i got that part, but how do i get from the 2nd equation to the third equation?
 
andrewkirk said:
The latter is not a deduction from the former. It is simply a definition, which the author is free to make, as the symbol B' has not been used up to that point.

The deduction is the equation immediately after the 'where...' part.
but how do i deduce it? what is step1? i don't know how to start.. from A'x'^2 + B'x'y' + ... + F = 0 to B' = 2(C - A)...
 
Like andrew has said, ##B'## is just a symbol used to represent the coefficient of ##x'y'##. The author could have retained the original form of the coefficient in terms of ##A##, ##B##, ##C##, and ##\theta##, but it will require more space. He chose ##B'## as the new coefficient for ##x'y'## because this symbol has not been used in the previous derivation.
 
i got it! just keep track and combine all the terms with x'y' then equate to zero and simplify. thanks guys!
 
can I get the name of the book?
 
mkeaudric said:
can I get the name of the book?
This thread is six years old. Don't count on a response from the participants.
 
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