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High Energy, Nuclear, Particle Physics
Understanding crossing symmetry: inverse beta decay
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[QUOTE="peguerosdc, post: 6384457, member: 660565"] [B]TL;DR Summary:[/B] When applying cross symmetry to ##\nu + n \rightarrow e^- + p##, why in the result ##\bar{\nu} + p \rightarrow e^+ + n## the arrow is pointing to the right? Hi! This is a very very noob question, but I am starting to get into particle physics and I don't understand the application of crossing symmetry in the inverse beta decay. Crossing symmetry says (from Griffiths) that, in a reaction [I]"any of these particles can be 'crossed' over to the other side of the equation, provided it is turned into its antiparticle, and the resulting interaction will also be allowed"[/I]. And the Compton scattering is mentioned as an example. Then, why another common example is the inverse beta decay used to detect the neutrino? The beta decay reaction is: $$ \nu + n \rightarrow e^- + p $$ And the inverse beta decay reaction is: $$ \bar{\nu} + p \rightarrow e^+ + n $$ But if you just do crossing symmetry to the beta decay equation, I understand that you should get the reverse reaction (with the arrow pointing to the other side): $$ e^+ + n \rightarrow \bar{\nu} + p $$ That is, I am: [LIST] [*]crossing ##e^-## from the right to the left as ##e^+## [*]crossing ##\nu## from the left to the right as ##\bar{\nu}## [*]leaving ##n## where it is [*]leaving ##p## where it is [/LIST] So, why is the arrow not pointing to the left in the correct inverse beta decay reaction? Thanks! [/QUOTE]
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High Energy, Nuclear, Particle Physics
Understanding crossing symmetry: inverse beta decay
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