Understanding Cylindrical Vector Fields: Can They Be Electrostatic?

  • Thread starter Thread starter taishar
  • Start date Start date
  • Tags Tags
    E&m
Click For Summary

Homework Help Overview

The discussion revolves around a vector field expressed in cylindrical coordinates and its potential classification as an electrostatic field. The vector field is given as F=(A)(s)(PhiHat) + (B)(z)(zhat), where A and B are constants. Participants are exploring the conditions under which such a field could be considered electrostatic.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the requirement for an electrostatic field to be curl-less and suggest taking the curl of the given vector field to check this condition. There is also mention of the relationship between electrostatic fields and scalar potentials.

Discussion Status

Some participants have provided reasoning related to the mathematical properties of electrostatic fields, particularly referencing the curl of a gradient. There is an acknowledgment of previous similar problems, indicating some familiarity with the topic, but no explicit consensus has been reached.

Contextual Notes

One participant expresses frustration from extended homework sessions, which may influence their current understanding and confidence in addressing the problem.

taishar
Messages
3
Reaction score
0
I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan
 
Physics news on Phys.org
taishar said:
I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan


an electrostatic field should be curl-less.

so... take the curl and see if it's zero or not.
 
i guess i should provide some justification for my answer so that you'll believe me! :-p

an electrostatic field can be written in terms of a scalar potential:

<br /> \mathbf{E} = -\nabla V.<br />


and it is a mathematical fact that
<br /> \nabla \times \nabla V = 0<br />

for any V.


So if the curl is strictly zero, this implies that E can be expressed in terms of a scalar potential (and not have a vector potential term), and this is enough to determine if E is a static field or not.
 
Duh. I knew I was just being stupid. I had to do a couple similar problems earlier. Gah. Thanks a bunch :) Too many hours doing homework...
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
13
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
1K