Understanding Cylindrical Vector Fields: Can They Be Electrostatic?

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SUMMARY

The discussion centers on determining whether the vector field F, defined in cylindrical coordinates as F=(A)(s)(PhiHat) + (B)(z)(zhat), can represent an electrostatic field. It is established that an electrostatic field must be curl-less, which is confirmed by taking the curl of F. The conclusion is that if the curl is zero, F can be expressed in terms of a scalar potential, thus qualifying it as an electrostatic field.

PREREQUISITES
  • Cylindrical coordinates in vector calculus
  • Understanding of electrostatic fields
  • Knowledge of curl and divergence operations
  • Familiarity with scalar and vector potentials
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  • Study the properties of curl in vector fields
  • Learn about scalar potential functions in electrostatics
  • Explore the mathematical implications of vector calculus identities
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This discussion is beneficial for physics students, electrical engineers, and anyone studying electromagnetism, particularly those interested in the characteristics of vector fields and electrostatics.

taishar
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I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan
 
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taishar said:
I'm given this:

A vector field is given in cylindrical coordinates as:

F=(A)(s)(PhiHat) + (B)(z)(zhat)

Where A and B are constants. Could F be an electrostatic field ? Why or why not ?

I kind of feel stupid asking this because I feel like I should know, but, I'm currently braindead after having just spent hours doing the previous 29 problems.

Thanks,
Dan


an electrostatic field should be curl-less.

so... take the curl and see if it's zero or not.
 
i guess i should provide some justification for my answer so that you'll believe me! :-p

an electrostatic field can be written in terms of a scalar potential:

<br /> \mathbf{E} = -\nabla V.<br />


and it is a mathematical fact that
<br /> \nabla \times \nabla V = 0<br />

for any V.


So if the curl is strictly zero, this implies that E can be expressed in terms of a scalar potential (and not have a vector potential term), and this is enough to determine if E is a static field or not.
 
Duh. I knew I was just being stupid. I had to do a couple similar problems earlier. Gah. Thanks a bunch :) Too many hours doing homework...
 

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