Understanding Derivatives in Scientific Calculations

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The discussion focuses on finding the derivative of the function s(t) = A Cos(wt + d) and confirming the correctness of the derivative s'(t) = -Aw Sin(wt + d). Participants clarify that all variables except t can be treated as constants during differentiation. To determine when the velocity s' equals zero, one can set wt + d equal to kπ, where k is any integer. The conversation emphasizes understanding the conditions under which the sine function equals zero, reinforcing that it occurs at multiples of π.
powp
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Hello

I am I finding the derivative for this right??

d = small delta

s(t) = A Cos(wt + d)


s'(t) = -A Sin(wt + d) * w

s'(t) = -Aw Sin(wt + d)

Is it correct to treat all the rest of the varibles as constants? My text does not give any examples with these.

All so what would make the velocity(s') = 0??

Thanks

Peter
 
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powp said:
Hello
I am I finding the derivative for this right??
d = small delta
s(t) = A Cos(wt + d)
s'(t) = -A Sin(wt + d) * w
s'(t) = -Aw Sin(wt + d)
Is it correct to treat all the rest of the varibles as constants? My text does not give any examples with these.
Yep.


powp said:
All so what would make the velocity(s') = 0??
Thanks
Peter

Well you got to ask yourself for what value(s) of t is s'(t) zero. To simplify the problem, make a change of variable y = wt + d. Find for what values of y is s'(y) zero, then find the corresponding values of t through t = (y-d)/w.
 
Thanks.

So if I am not given any values for w,d, or A would I just state that the velocity is 0 when wt + d = 0?
 
powp said:
Thanks.
So if I am not given any values for w,d, or A would I just state that the velocity is 0 when wt + d = 0?
Is a sine only zero when the argument is zero?
 
no it can be 0 at nPi. Is this correct?
 
Indeed, sin(x) is 0 when x is k\pi[/tex] with k an integer.
 
thanks for your help
 
You're welcome :smile:
 

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