Understanding e in Algebraic Equations

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SUMMARY

The discussion focuses on solving the algebraic equation 120.3 - e^(0.15x) = e^(0.15x). The user correctly simplifies the equation to 120.3 - 2e^(0.15x) = 0, allowing them to isolate e^(0.15x). By dividing both sides by 2, they determine that e^(0.15x) = 60.15. The final step involves taking the natural logarithm to solve for x, confirming the user's understanding of algebraic manipulation involving exponential functions.

PREREQUISITES
  • Understanding of exponential functions and their properties
  • Knowledge of algebraic manipulation techniques
  • Familiarity with natural logarithms
  • Basic skills in solving equations
NEXT STEPS
  • Learn how to apply natural logarithms to solve exponential equations
  • Study the properties of e and its applications in calculus
  • Explore techniques for solving complex algebraic equations
  • Practice integration problems involving exponential functions
USEFUL FOR

Students studying algebra, particularly those tackling exponential equations and integration problems, as well as educators looking for examples of algebraic manipulation involving the constant e.

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Homework Statement



I am confused because of the e, I don't know how to do algebra with them. I need to solve it and set it to 0 for an integration problem.

Homework Equations



Solve: 120.3 - e^(.15x) = e^(.15x)

The Attempt at a Solution



= 120.3 - e^(.15x) - e^(.15x)

I can set it to zero by trial and error, but is this part ^ at least correct?
 
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Add e^.15x to both sides... Gives you 2e^.15x... Divide by 2... Do you know how to solve for e after? (you should)
 
iRaid said:
Add e^.15x to both sides... Gives you 2e^.15x... Divide by 2... Do you know how to solve for e after? (you should)

Thanks for the help, got it :-)
 

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