Understanding Energy of a Signal: Integral & Absolute Value Sign

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Discussion Overview

The discussion revolves around the mathematical definition of the energy of a signal, specifically focusing on the integral of the magnitude of the signal squared and the implications of the absolute value sign in this context. Participants explore the treatment of absolute values in integrals, particularly for real-valued and complex-valued functions.

Discussion Character

  • Conceptual clarification
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion regarding the integral of the magnitude of a signal squared and the role of the absolute value sign.
  • Another participant clarifies that for real-valued functions, the absolute values are unnecessary since squaring the function eliminates the need for them.
  • A further explanation is provided for complex-valued functions, indicating that the magnitude squared is the sum of the squares of the real and imaginary parts.
  • Some participants reflect on the simplicity of the explanation provided.

Areas of Agreement / Disagreement

Participants generally agree on the treatment of absolute values for real-valued functions, while the discussion remains open regarding the implications for complex-valued functions.

Contextual Notes

There is a lack of discussion on specific examples or cases where the absolute value might affect the interpretation of the integral, leaving some assumptions unaddressed.

cybernoodles
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Hi All,

I am confused about what is meant in the mathematical definition for the energy of a signal. Why is it the integral of the magnitude of the signal squared?

∫(|f(t)|^2)

How do I deal with the absolute value sign? I do not have much experience with absolute value signs in integrals. I did do a search but am still confused. How do I even know if a function will need to be readjusted according to the absolute value sign and, if so, how do I rewrite the function so that it obeys the absolute value condition?
 
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If f(t) is a real-valued function the absolute values just "go away", because |f\,|^2 = |f\,| \times |f\,| = f\,{}^2
is always true - it doesn't matter whether f is positive, negative, or zero.

If f is a complex-valued function and f(t) = p(t) + i\,q(t), then
|f\,|^2 = p^2 + q^2
 
Wow that was so simple. Thanks!
 
cybernoodles said:
Wow that was so simple.

Somebody once said, "There are only two types of math problem: the trivial ones that you know how to solve, and the impossible ones that you don't" :smile:
 

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