Understanding Final Value Theorem in Laplace Transform: Tips & Examples

Click For Summary
SUMMARY

The discussion centers on the Final Value Theorem (FVT) in the context of Laplace Transforms, specifically addressing the implications of complex conjugate poles on the imaginary axis. It is established that if such poles exist, the system's output will contain sinusoidal components, rendering the final value undefined. The confusion arises from the application of the FVT to find DC gain without proper multiplication by "s" in the s-domain representation of the transfer function H(s). The participants clarify that the presence of a unit step input cancels "s" with "1/s", but the initial concern regarding the definition of the output remains valid.

PREREQUISITES
  • Understanding of Laplace Transforms
  • Knowledge of Final Value Theorem
  • Familiarity with transfer functions and their representations
  • Basic concepts of control systems and stability analysis
NEXT STEPS
  • Study the implications of complex conjugate poles in control systems
  • Learn about the conditions under which the Final Value Theorem is applicable
  • Explore the relationship between Laplace Transforms and system stability
  • Investigate the role of unit step inputs in Laplace Transform analysis
USEFUL FOR

Control system engineers, electrical engineers, and students studying signal processing or systems analysis will benefit from this discussion, particularly those looking to deepen their understanding of the Final Value Theorem and its applications in Laplace Transforms.

zoom1
Messages
63
Reaction score
0
http://fourier.eng.hmc.edu/e102/lectures/Laplace_Transform/node17.html

On that page about final value theorem, it says that;

If there are pairs of complex conjugate poles on the imaginary axis, will contain sinusoidal components and is not defined.

However at the bottom of the page, in order to find the DC gain, it uses Final value theorem.

Ok, well, let's assume somehow he put "0" where he saw "s". How about multiplication with "s" for final value theorem on s domain ?
He didn't even multiplied the H(s) with "s" ?

Confused.
 
Engineering news on Phys.org
zoom1 said:
http://fourier.eng.hmc.edu/e102/lectures/Laplace_Transform/node17.html

On that page about final value theorem, it says that;



However at the bottom of the page, in order to find the DC gain, it uses Final value theorem.

Ok, well, let's assume somehow he put "0" where he saw "s". How about multiplication with "s" for final value theorem on s domain ?
He didn't even multiplied the H(s) with "s" ?

Confused.

Seems like I missed the unit step input, so "s" will be canceled by "1/s". However still the first question holds. System has complex conjugates lying on the left side of the s plane. Which makes the output sinusoidal. So, x(infinite) shouldn't be defined.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K