Understanding Formula Transition: Solving for curlB and divJ in Electromagnetism

Click For Summary
The discussion focuses on the transition between integral equations in electromagnetism, specifically how to derive the equation curlB = με(dE/dt) + μJ from the given integral forms. Participants suggest using Stoke's theorem to facilitate this transition and emphasize the correct formatting for LaTeX code to ensure proper display of equations. There are repeated attempts to clarify the use of "[tex]" for formatting, indicating ongoing issues with displaying the mathematical expressions correctly. The conversation highlights the importance of precise notation in mathematical discussions. Overall, the thread combines technical discussion with troubleshooting LaTeX formatting issues.
nhrock3
Messages
403
Reaction score
0
157lu1s.jpg

\oint Bdl=\mu\int JdA+\mu\frac{{d}}{dt}\int EdA

\int(curlB)dA=\mu\int divJdV+\mu\frac{{d}}{dt}\int divEdV

how to go from the above integral equation to the bottom equation

<br /> <br /> curlB=\mu\varepsilon\frac{{dE}}{dt}+\mu J<br /> <br />
 
Last edited:
Physics news on Phys.org
I think there are something wrong with your LaTeX-codes.
 
nhrock3 said:
\oint Bdl=\mu\int JdA+\mu\frac{{d}}{dt}\int EdA

\int(curlB)dA=\mu\int divJdV+\mu\frac{{d}}{dt}\int divEdV

how to go from the above integral equation to the bottom equation

<br /> <br /> curlB=\mu\varepsilon\frac{{dE}}{dt}+\mu J<br /> <br />
Try using and instead of and.

RGV
 
nhrock3 said:
\oint Bdl=\mu\int JdA+\mu\frac{{d}}{dt}\int EdA

\int(curlB)dA=\mu\int divJdV+\mu\frac{{d}}{dt}\int divEdV

how to go from the above integral equation to the bottom equation

<br /> <br /> curlB=\mu\varepsilon\frac{{dE}}{dt}+\mu J<br /> <br />
Looks to me like an application of Stoke's curl theorem:
\int_S \nabla\times F dS= \oint_{\partial S} F\cdot ds
 
Ray Vickson said:
Try using and instead of and.

RGV
What Ray wrote was [ tex] and [ /tex], but without the extra space inside each pair of brackets. In other words, don't use upper case (TEX); use lower lower case (tex).
 
i tried i switched to
\oint Bdl=\mu\int JdA+\mu\frac{{d}}{dt}\int EdA

\int(curlB)dA=\mu\int divJdV+\mu\frac{{d}}{dt}\int divEdV

how to go from the above integral equation to the bottom equation

<br /> <br /> curlB=\mu\varepsilon\frac{{dE}}{dt}+\mu J<br /> <br />

still no formula showing
 
Ray Vickson said:
Try using and instead of and.

RGV
This should have said "&quot; and &quot;" instead of and.
I guess the first part was dropped because I forgot to put the "&quot; in<br /> quotes. So, that means that you remove the quotes when you use them.<br /> <br /> RGV
 
157lu1s.jpg
 
AArgh! This still has not gotten through. I mean
use "[ t - e - x]" and "[ / t - e - x ]" (removing spaces and
hyphens, or course). Let's see if *this* gets through.

RGV
 
  • #10
i uploaded a photo could you help with my question
Arrggg :)
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
511
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 24 ·
Replies
24
Views
3K
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
6K
Replies
3
Views
2K