Understanding Friction: The Basics of Physics and How to Apply Formulas

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    Friction Theory
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Discussion Overview

The discussion revolves around understanding the concept of friction in physics, particularly focusing on the application of formulas related to frictional forces. Participants explore both theoretical aspects and practical problem-solving related to homework assignments.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Exploratory

Main Points Raised

  • One participant expresses difficulty in understanding the instructor's teaching methods and the application of friction formulas.
  • Another participant suggests posting specific problems for more targeted help.
  • Several participants clarify that the coefficient of friction is dimensionless and explain its role in relating forces.
  • One participant presents two homework problems involving friction and seeks assistance in solving them.
  • Another participant explains the relationship between frictional force and normal force, emphasizing that the coefficient of friction is proportional to these forces.
  • Participants discuss the need to account for negative acceleration when calculating distance slid due to friction.
  • One participant acknowledges confusion over their calculations and receives feedback on correcting their approach.

Areas of Agreement / Disagreement

Participants generally agree on the nature of the coefficient of friction being dimensionless and its role in physics problems. However, there is no consensus on the specific solutions to the homework problems, as one participant's answer does not match the textbook, leading to further discussion and clarification.

Contextual Notes

Some participants mention the importance of understanding the underlying concepts rather than just memorizing equations. There are unresolved issues regarding specific calculations and the assumptions made in the problems presented.

Who May Find This Useful

Students struggling with introductory physics concepts, particularly those related to friction and its applications in problem-solving.

  • #31
Originally posted by chroot
F is the force, o is the angle, 21 degrees. Think about it this way: the horizontal component of the force is F cos(o), while the vertical component is F sin(o).

- Warren

so you sub .57 in for F? then multiply it by cos or sin
 
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  • #32
Originally posted by izmeh
so you sub .57 in for F? then multiply it by cos or sin
No. F is the magnitude of the force, the quantity you're trying to find. 0.57 is [mu].

Solve this equation for F:

F cos(21 deg) = [mu] (m g + F sin(21 deg))

- Warren
 

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