Understanding Galilean Transformation: A Troubleshooting Guide

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SUMMARY

The discussion focuses on the Galilean transformation equations used to convert coordinates between two reference frames, specifically addressing the confusion between the coordinates of stationary and moving observers. The stationary observer perceives an object at coordinates (x+n, y, z, t), while the moving observer sees it at (x', y', z', t'), where x' is calculated as x' = x - vt. The key takeaway is the correct application of the transformation, which clarifies that x' = n - vt when n is the distance observed by the stationary observer.

PREREQUISITES
  • Understanding of basic physics concepts, particularly relative motion
  • Familiarity with coordinate systems in physics
  • Knowledge of the Galilean transformation equations
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the derivation of the Galilean transformation equations
  • Explore examples of relative motion in different reference frames
  • Learn about the implications of Galilean transformations in classical mechanics
  • Investigate the differences between Galilean and Lorentz transformations
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Students of physics, educators teaching classical mechanics, and anyone interested in understanding the principles of relative motion and coordinate transformations.

xiankai
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i have trouble taking the equations given, that is the conversion of one coordinate frame to another.

lets assume at the starting point there are two observers (coordinates (x,y,z,t)).

one observer moves in the x direction and the other observer stays still. the observer that moves has the coordinates of x',y',z',t' at any time.

the stationary observer sees an object in the x-direction, n units ahead. for the moving observer, at a particular instant of time, he sees it as n-vt ahead, where v is the relative velocity between the two frames of reference, and t is the time elapsed from the start till the instant.

as the coordinates of object are (x+n,y,z,t) or (x'+n-vt,y',z',t')

hence..

x+n = x'+n-vt

x = x' - vt

x' = x + vt

which isn't the result to be arrived at. can someone help me? i tried doing a search but it seems to elementary a problem to feature as a major stumbling block, couldn't find any topics on it. ><
 
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xiankai said:
the stationary observer sees an object in the x-direction, n units ahead. for the moving observer, at a particular instant of time, he sees it as n-vt ahead, where v is the relative velocity between the two frames of reference, and t is the time elapsed from the start till the instant.

as the coordinates of object are (x+n,y,z,t) or (x'+n-vt,y',z',t')
You seem to be confusing the meaning of x and x'. If the stationary observer sees the object at x = n, the moving observer sees the object at x' = x - vt = n - vt.

The coordinates of the object are simply (x, y, z, t) and (x', y', z', t'), related by the usual Galilean transformation.
 

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