Understanding Lenz's Law and the Right Hand Rule in Electromagnetic Induction

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SUMMARY

This discussion centers on the application of Lenz's Law and the Right Hand Rule in the context of electromagnetic induction. The participants analyze a scenario involving two loops of wire, where the magnetic field outside loop 1 is directed out of the page, but due to increasing resistance, the field weakens. According to Lenz's Law, loop 2 generates a current to oppose this change, resulting in a clockwise current direction. However, the correct answer to the posed question is choice A, as the magnetic flux from the left loop influences the right loop, necessitating a current flow to maintain the magnetic field direction.

PREREQUISITES
  • Understanding of Lenz's Law
  • Familiarity with the Right Hand Rule
  • Basic concepts of electromagnetic induction
  • Knowledge of magnetic flux and its implications
NEXT STEPS
  • Study the mathematical formulation of Lenz's Law
  • Explore the applications of the Right Hand Rule in various electromagnetic scenarios
  • Investigate the relationship between magnetic flux and induced current
  • Review examples of electromagnetic induction in real-world applications
USEFUL FOR

Students of physics, educators teaching electromagnetic theory, and anyone seeking to deepen their understanding of electromagnetic induction principles.

Rmehtany
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Homework Statement


upload_2016-4-8_19-34-1.png


Homework Equations


Not really? I just used the right hand rule and Lenz's law

The Attempt at a Solution



By the right hand rule, outside of loop 1, the magnetic field is out of the page. However, increasing resistance means that field is weakening. We know by Lenz's law that loop 2 will try to replace that field, so outside of loop two should be an out of the page magnetic field. This means the current direction is Clockwise, giving choice B

However, the answer is choice A. Why?
 
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Magnetic flux from the left loop will be linked with the right loop. What is the direction of field in the right loop because of the current flowing through the left loop? Since the current in the left loop is decreasing, to maintain the previous direction(and magnitude) of the field, current will flow through the right loop.
 
Wouldn't the field be out of the page because outside of the left ring, the field is out of the page?
 
Rmehtany said:
Wouldn't the field be out of the page because outside of the left ring, the field is out of the page?
Yes. But if that field is collapsing, in what direction should the current flow in order to resist this "change"?
 

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