Understanding Linear Functionals: Help Me w/ Example Problem!

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Homework Help Overview

The discussion revolves around understanding linear functionals within the context of linear algebra. The original poster presents an example problem involving two expressions and seeks clarification on whether they qualify as linear functionals.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definitions of linear functionals and examine the properties that need to be satisfied. One participant attempts to verify the properties of linearity for the given expressions.

Discussion Status

The discussion includes attempts to analyze the properties of the proposed linear functionals. Some guidance is provided regarding the importance of definitions and the verification of properties, but there is no explicit consensus on the correctness of the examples presented.

Contextual Notes

The original poster is preparing for a final exam and is under time constraints, which may influence the depth of the discussion. There is an emphasis on understanding rather than simply obtaining answers.

wurth_skidder_23
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I am studying for a final I have tomorrow in linear algebra, and I am still having trouble understanding linear functionals. Can someone help me out with this example problem, walk me through it so I can understand exactly what a linear functional is?

Is the following a linear functional?

[tex]\ y (x)=\int_0^1\ t^2 x(t) \, dx[/tex]
[tex]\ y (x)=x(-2)+\int_0^1\ x(t^2)\, dt[/tex]
 
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Always start by going back to the definitions.
 
For the second one, which is basically just an addition to the first, is this correct?

Property 1 of a linear functional is satisfied as follows:
[tex]\ y (x+z)=x(-2)+z(-2)+\int_0^1\ (x(t^2)+z(t^2))\, dt[/tex]
[tex]\ y (x+z)=x(-2)+\int_0^1\ x(t^2)\, dt + z(-2)+\int_0^1\ z(t^2)\, dt[/tex]
[tex]\ y (x+z)=y(x)+y(z)[/tex]

Property 2 of a linear function is satisfied similarly:
[tex]\ y(a x)=a x(-2)+\int_0^1\ a x(t^2)\, dt[/tex]
[tex]\ y(a x)=a (x(-2)+\int_0^1\ x(t^2)\, dt)[/tex]
[tex]\ y(a x)=a y(x)[/tex]
 
Last edited:
It's as easy as that.
 

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