Understanding Momentum in Continuous Mass Flow Problems

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
1 replies · 3K views
unscientific
Messages
1,728
Reaction score
13

Homework Statement



From 2.2 Worked Examplehttp://ocw.mit.edu/courses/physics/8-01sc-physics-i-classical-mechanics-fall-2010/continuous-mass-flow/MIT8_01SC_coursenotes19.pdf"

Emptying a Freight Car - A freight car of mass mc
contains a mass of sand ms
At t = 0 a constant horizontal force of magnitude F is applied in the direction of rolling and at the same time a port in the bottom is opened to let the sand flow out at the constant rate b = dms/ dt . Find the speed of the freight car when all the sand is gone. Assume that the freight car is at rest at t = 0 .

Homework Equations



It is written that the momentum of vehicle at time t is ( [tex]\Delta[/tex]m + m ) v

The Attempt at a Solution



Shouldn't the momentum of the vehicle at time t be just (mc(t))v ? by adding [tex]\Delta[/tex]m you're doing it twice!

I don't understand how they got the momentum for time t+ [tex]\Delta[/tex]t too! shouldn't it be (mc - [tex]\Delta[/tex]m)(v + [tex]\Delta[/tex]v)?
 
Last edited by a moderator:
on Phys.org
unscientific said:

Homework Statement



The Attempt at a Solution



Shouldn't the momentum of the vehicle at time t be just (mc(t))v ? by adding [tex]\Delta[/tex]m you're doing it twice!

I don't understand how they got the momentum for time t+ [tex]\Delta[/tex]t too! shouldn't it be (mc - [tex]\Delta[/tex]m)(v + [tex]\Delta[/tex]v)?

I would agree with you that the momentum at time t is (mc(t))v. But disagree with the momentum at t+ [tex]\Delta[/tex]t. It should be
[tex]P(t+\delta t)=(m-\delta m)(v+\delta v)+\delta mv.[/tex]

So the final result should remain as [tex]F=m\frac{dv}{dt}.[/tex]