Understanding Physics for the Beer Mug Problem

[Let It Be]

1. A bartender slides a beer mug at 1.50m/s towards a customer at the end of a frictionless bar that is 1.2m tall. the customer makes a grab for the mug and misses, and the mug sails of the end of the bar. What are the speed and direction of the mug at impact?


2. Vx=Vocosθ
Vy=Vosinθ
V=√Vx^2+Vy^2
θ=tan-1(Vy/Vx)


3. The correct answer apparently is 5.08m/s and θ=-72.8°. I didn't get that...

 

[AlephZero]

The equations you give are OK to find the speed and direction, but you need some more equations to find Vx and Vy when the mug hits the floor.

 

[Let It Be]

The equations you give are OK to find the speed and direction, but you need some more equations to find Vx and Vy when the mug hits the floor.

I don't know how to solve the problem with the equations I do have though...

 

[217 MeV]

How do you think v_x and the sliding velocity compare?

Think about it, don't try use the equations!

 

[Let It Be]

How do you think v_x and the sliding velocity compare?

Think about it, don't try use the equations!

I know I need to find Vf for the speed when the mug hits the floor. And then direction idk

 

[217 MeV]

Well, start with the x-component of v_f. What will that be?

Remember there's no friction whilst the mug is sliding, and I assume there is no air resistance.