robertjford80 Messages 388 Reaction score 0 Thread starter May 29, 2012 #1 I don't see how this follows.
phyzguy Science Advisor Messages 5,317 Reaction score 2,400 May 29, 2012 #2 What don't you see? If you do the substitution, the h's cancel, one of the c's cancel, and one of the lambda's cancel, leaving the result. What are you missing?
What don't you see? If you do the substitution, the h's cancel, one of the c's cancel, and one of the lambda's cancel, leaving the result. What are you missing?
jtbell Staff Emeritus Science Advisor Homework Helper 2025 Award Messages 16,110 Reaction score 8,373 May 29, 2012 #3 If your problem is with the approximation in the second line, consider the power series for ex: $$e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + ...$$
If your problem is with the approximation in the second line, consider the power series for ex: $$e^x = 1 + x + \frac{x^2}{2!} + \frac{x^3}{3!} + ...$$