Understanding Relative Motion in Circular Motion

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Discussion Overview

The discussion revolves around understanding relative motion in circular motion, specifically focusing on the acceleration of one object relative to another in a circular path. Participants explore the concepts of tangential and radial acceleration in the context of a homework problem.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants present the equation for relative acceleration as a_A/B = a_A - a_B, with specific values for a_A and a_B given in terms of angular velocity and radius.
  • There is confusion about the direction of the acceleration vectors for objects A and B, with some participants questioning the correctness of their expressions.
  • Participants discuss whether the acceleration should be tangential or radial, with some asserting it should be tangential due to constant radius, while others argue it should only have radial acceleration.
  • One participant clarifies that the radial acceleration for B points from point B to point O, and for A, it points from point A to point O.
  • A later reply confirms the correct relative acceleration after considering the radial directions of the accelerations for A and B.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the nature of the acceleration (tangential vs. radial) and the correctness of their initial expressions. The discussion evolves as participants refine their understanding, but no consensus is reached on the initial interpretations.

Contextual Notes

Participants rely on specific assumptions about the motion being circular and the constancy of angular velocity, which may not be explicitly stated. The discussion also reflects uncertainty in the application of vector directions in the context of relative motion.

nysnacc
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Homework Statement


13.164.png


Homework Equations


a= omega^2*r

The Attempt at a Solution


a_A/B = a_A - a_B

a_A = 10^2*r (-î)
a_B = 10^2*r (+ĵ)

a_A/B = 10^2*r (-î) - 10^2*r (+ĵ)
=> -200 î -200 ĵ

why is the answer 200 î -200 ĵ (accelerate in +î direction) ?
 
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nysnacc said:

Homework Statement


View attachment 105735

Homework Equations


a= omega^2*r

The Attempt at a Solution


a_A/B = a_A - a_B

a_A = 10^2*r (-î)
a_B = 10^2*r (+ĵ)

a_A/B = 10^2*r (-î) - 10^2*r (+ĵ)
=> -200 î -200 ĵ

why is the answer 200 î -200 ĵ (accelerate in +î direction) ?
The question is asking for the acceleration of A relative to B. What's the acceleration at A and at B independently?

Hint: Check the direction of acceleration vectors.
 
Last edited:
Student100 said:
The question is asking for the acceleration of A relative to B. What's the acceleration at A and at B independently?

Hint: Check the direction of acceleration vectors.

Err... isn't my expression correct..?

a_A = 10^2*r (-î). A is going -x, -y direction
a_B = 10^2*r (+ĵ). B is going -x, +y direction
 
nysnacc said:
Err... isn't my expression correct..?

a_A = 10^2*r (-î). A is going -x, -y direction
a_B = 10^2*r (+ĵ). B is going -x, +y direction

No. Should your acceleration be tangential or radial to the disk? Remeber the disk has constant angular velocity.
 
Student100 said:
No. Should your acceleration be tangential or radial to the disk? Remeber the disk has constant angular velocity.
should be tangential because constant radius??
 
nysnacc said:
should be tangential because constant radius??

Actually it should only have radial acceleration. Can you see why?
 
because constant rotation?
 
so the a_r for B is pointing from point B to Point O
and for A it is pointing from Point A to Point O?
 
nysnacc said:
so the a_r for B is pointing from point B to Point O
and for A it is pointing from Point A to Point O?

Exactly, so what's your relative acceleration now?
 
  • #10

so the a_r for B is omega^2*r (-i)
a_r for A is omega^2*r (-j)

a_A/B = a_A - a_B = -omega^2*r (j) - -omega^2*r (i)
rearrange = omega^2*r (i) - omega^2*r (j)

Got it! Thanks!
 

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