Understanding RLC Circuits: Calculating Current in a Series Circuit

Click For Summary
SUMMARY

The discussion focuses on solving a series RLC circuit with an electromotive force described by E=200e^(-100t) V, a resistor of 80 ohms, an inductor of 0.2 H, and a capacitor of 5x10^-6 F. The initial conditions are zero current and charge on the capacitor. The differential equation derived from Kirchhoff's Voltage Law (KVL) is v''+(R/L)v'+v/(LC)=E/(LC). To solve this second-order differential equation, the recommended approach is to use the Laplace transform, followed by partial fraction decomposition for easier inversion.

PREREQUISITES
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Knowledge of differential equations
  • Familiarity with Laplace transforms
  • Basic concepts of RLC circuit components (resistor, inductor, capacitor)
NEXT STEPS
  • Study the application of Laplace transforms in solving differential equations
  • Learn about partial fraction decomposition techniques
  • Explore the behavior of RLC circuits under different driving functions
  • Investigate initial value problems in the context of electrical circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or solving RLC circuit problems.

kings13
Messages
27
Reaction score
0
A series RLC circuit has an electromotive force given by E=200e^(-100t) V, a resistor of 80 ohms, an inductor of 0.2 H, and capacitor of 5x10^-6 F. If the initial current and charge on the capacitor are zero, find the current at any time t>0.

How on Earth do i start this?!
 
Physics news on Phys.org
First, write a differential equation using KVL. Call the voltage across the cap, v(t). Then, the voltage across the inductor is Ldi/dt. The voltage across the resistor is iR. The driving voltage is E. Now, since i is going into a cap, we know that i=Cv', where v' is dv/dt. Then, putting it all together and dividng by LC gives v''+(R/L)v'+v/(LC)=E/(LC), where E is the EMF driving the circuit. Now, before you can solve this equation, you need to figure out your initial values. What does i(0)=0 imply about v'(0)? Use i(t)=Cv'(t) to find this initial value. Now, what does q(0)=0 imply about v(0)? Note that C=q(t)/V(t), so V(t)=q(t)/C.

Now you have a second order differential equation and you have two initial values to solve it. You can use any method you'd like to solve this equation, but you may find it difficult because of the driving term, E. I would suggest a Laplace transform. Then, if you get a weird answer in the s domain, use partial fractions to break it into parts which you can easily invert.
 

Similar threads

  • · Replies 32 ·
2
Replies
32
Views
4K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 15 ·
Replies
15
Views
6K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
44
Views
6K
  • · Replies 1 ·
Replies
1
Views
3K