Understanding Rotational Energy of a Fan Impeller

[Turv]

Hi,

I'm trying to understand the rotational energy of a fan impeller.

I understand RE = 1/2Iw^2

So therefore an impellor with an inertia of 50 kg m^2 spinning at 1440 rpm

= 568405 J

my question is does this figure need to be divided by 3600000 J to give Kw hours?

 

[Naty1]

Correct: 1KWH equals 3.6 x 10⁶ joules