Understanding the (1+1/n)^n Problem: The Last Term in Binomial Expansion

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SUMMARY

The discussion centers on the last term in the binomial expansion of the expression (1+1/n)^n. Participants clarify that the last term can be represented as (1/n!)(1-1/n)(1-2/n)...(1-(n-1)/n), which simplifies to (1/n!)(n(n-1)...1)/n^n. Both representations are confirmed to be equivalent, demonstrating a deeper understanding of binomial coefficients and factorials in combinatorial mathematics.

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MathematicalPhysicist
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it's rather a bypass question, not a direct question about 'e'.

the last term in the binomial expansion of (1+1/n)^n is according to my text:
(1/n!)(1-1/n)(1-2/n)...(1-(n-1)/n)
while it should be (1/n!)(n(n-1)...1)/n^n

okay, these two terms are almost identical, the first equals
(with disregarding of 1/n!):
((n-1)(n-2)...1)/n^n
and second one is the first multiplied by n, then what is the problem.

i assume it's with me ( just kidding).
 
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(1/n!)(1-1/n)(1-2/n)...(1-(n-1)/n)
= (1/n!)(n-1)(n-2)...(n-(n-1))/n^(n-1)
= (1/n!)(n-1)...1/n^(n-1)
= (1/n!)(n(n-1)...1)/n^n

so, they're the same
 
okay i think i can see it, thanks.
 

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