Understanding the Delta Function: Integrating from -∞ to ∞

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SUMMARY

The delta function, represented as δ(r-r')=∫-∞∞exp(i(r-r')k)dk, is a formal expression that lacks meaningful limits as x approaches ±∞. This integral is valid in the context of tempered distributions, where the Dirac delta function possesses a Fourier transform. Specifically, it is established that the Fourier transform of the delta function is constant, denoted as ##\hat\delta = 1##. The equation illustrates that the Inverse Fourier transform of the constant function 1 yields the Dirac delta function.

PREREQUISITES
  • Understanding of Fourier transforms
  • Familiarity with tempered distributions
  • Knowledge of complex analysis
  • Basic principles of mathematical integration
NEXT STEPS
  • Study the properties of tempered distributions in detail
  • Explore the applications of the Fourier transform in physics
  • Learn about the Inverse Fourier transform and its implications
  • Investigate the role of the delta function in signal processing
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Mathematicians, physicists, and engineers interested in advanced calculus, signal processing, and the theoretical foundations of distributions.

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My book loves to represent the delta function as:

δ(r-r')=∫-∞exp(i(r-r')k)dk

Now I can understand this formula if the integration was over the unit circle since. But this is an integration for which the antiderivative as no meaningful limit as x->±∞
 
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The integral written is only true as formality. What's really going on is that Dirac is a tempered distribution, and hence has a Fourier transform. It can be shown that ##\hat\delta = 1##. What the equation is trying to say is that the Inverse Fourier of the constant 1 is Dirac delta.
 

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