Understanding the Dirac Delta function

In summary, the Dirac delta function is a generalized function that can be defined as a distribution or measure. It is defined by its behavior in an integral, where ∫f(x)δ(x)dx = f(0). The expression ∫δ(x-y)f(x)dx = f(y) is a more accurate representation than the incorrect expressions provided. Additionally, the integral cannot be omitted and the second expression does not make sense.
  • #1
redtree
332
15
I just want to make sure that I am understanding the Dirac Delta function properly. Is the following correct?:

For two variables ##x## and ##y##:
\begin{equation}
\begin{split}
\delta(x-y) f(x) &= f(y)
\end{split}
\end{equation}

And:
\begin{equation}
\begin{split}
\delta(x-x) f(x) &= f(x)
\end{split}
\end{equation}
 
Physics news on Phys.org
  • #2
Neither of those is correct.
 
  • #3
The Dirac delta is not a function in the traditional sense, it can be rigorously defined either as a distribution or as a measure.
Ssnow
 
  • #4
The Dirac delta function is defined as a generalized function by its behavior in an integral: ∫f(x)δ(x)dx = f(0).
So in your question, ∫δ(x-y)f(x)dx = f(y) would make better sense than your expression (1). The integral can not be omitted. Your expression (2) does not make sense to me.
 

Similar threads

Replies
10
Views
2K
Replies
2
Views
2K
Replies
1
Views
376
Replies
2
Views
2K
Replies
8
Views
2K
Back
Top