Understanding the divergence theorem

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SUMMARY

The divergence theorem relates the flux of a vector field through a closed surface to the divergence of the field within the volume enclosed by that surface. Specifically, it states that the total flux out of a volume is equal to the integral of the divergence over that volume, expressed mathematically as ∫∇E dV = ∫E·n dS. The divergence of a vector field quantifies the net flux per unit volume, indicating whether field lines are converging or diverging at a point. In the context of electromagnetism, this is often associated with Maxwell's equations, where the divergence of the electric field is related to the charge density within the volume.

PREREQUISITES
  • Understanding of vector calculus, specifically divergence and gradient operations.
  • Familiarity with Maxwell's equations and their physical implications.
  • Knowledge of surface integrals and volume integrals in multivariable calculus.
  • Basic concepts of electric fields and charge distributions.
NEXT STEPS
  • Study the mathematical derivation of the divergence theorem in vector calculus.
  • Explore Maxwell's equations, focusing on the relationship between divergence and charge density.
  • Learn about surface integrals and their applications in physics.
  • Investigate practical applications of the divergence theorem in electromagnetism and fluid dynamics.
USEFUL FOR

Students of physics, particularly those studying electromagnetism, vector calculus, and engineering, as well as educators looking to clarify the concepts of divergence and the divergence theorem.

polaris90
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I'm having some trouble understanding what divergence of a vector field is in my "Fields and Waves" course. Divergence is defined as divE=∇E = (∂Ex/∂x) + (∂Ey/∂y) + (∂Ez/∂z). As far as I understand this gives the strength of vector E at the point(x,y,z).
Divergence theorem is defined as ∫∇Eds, where ds represents the area or volume of the vector field. In other words, I understand it as the overall strength of the vector field at a group of points composing a volume defined by the integral.
Could someone verify this for me?
 
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At least pointing out what's wrong would help.
 
Divergence is not the strength of the field at a particular point. Divergence is the total amount of flux going into or leaving a volume at that point.
 
Thanks, so would it be correct to say that divergence theorem refers to the amount of flux passing through a surface or volume?
 
Almost. Not through the volume, but rather being sourced or swallowed by the volume. For example, you cited ∇E which is often seen as part of one of Maxwell's equations. In this case, ∇E = q, which says the flux leaving a volume (the divergence) is equal to the amount of charge q contained in the volume. The charge q is sourcing e-field flux in this example.
 
thank you all, that was very helpful
 
polaris90 said:
Thanks, so would it be correct to say that divergence theorem refers to the amount of flux passing through a surface or volume?

Divergence theorem just makes it very clear.
What is flux?
Product of normal component of vector field and the surface element.

What is divergence of vector field?
Net flux diverging per unit volume.

What is Divergence?
Positive or negative divergence of a vector field at a point indicates whether the lines of force are diverging or converging at that given point.

By divergence theorem... The flux diverging from a given volume will be equal to the flux passing through the closed surface enclosing the volume.

For your question, the flux as explained above will be 'passing' through the closed surface enclosing the volume and the volume will be acting as the source of flux.

Consider a charge kept at the center of the sphere. The charge enclosed by this volume will be equal to electric flux lines passing normal to the closed surface. So the volume here is the source of flux whereas the flux is passing through the surface of the sphere.

Simple :]

Correct me if i am wrong.
 
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