Understanding the Doppler Effect: Solving the Bat Problem

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The discussion centers on solving a Doppler effect problem involving a bat and an insect. The bat is first treated as the sound source, emitting a 40.0-kHz chirp, and then as the observer receiving a 40.4 kHz echo. The key confusion arises from why both frequencies are set to the reflected wave in the second step. It's clarified that the first step calculates the frequency observed by the insect, which then acts as the source frequency for the bat's observation. Correctly distinguishing between the observed frequency and the source frequency is crucial for accurate calculations in this two-stage process.
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Homework Statement
A bat flying at 4.10 m/s is chasing an insect flying in the same direction. The bat emits a 40.0-kHz chirp and receives back an echo at 40.4 kHz. (Take the speed of sound in air to be 340 m/s.)
Relevant Equations
f_o=f_s(v+v_o/v-v_s)
I'm struggling a lot with this problem on the Doppler effect. I understand the first step which is to treat the bat as the source of the emitted sound, giving

1614718292037.png


And the second to treat the bat now as the observer, but instead of using f_b on the left the solution involves setting both frequencies to the reflected wave.
1614718268174.png

I understand there should 2 different variables here for the equation to make sense but I need help understanding why the second step involves setting the two frequencies the same. Thanks in advance!
 
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physicsfan999 said:
Homework Statement:: A bat flying at 4.10 m/s is chasing an insect flying in the same direction. The bat emits a 40.0-kHz chirp and receives back an echo at 40.4 kHz. (Take the speed of sound in air to be 340 m/s.)
Relevant Equations:: f_o=f_s(v+v_o/v-v_s)

I'm struggling a lot with this problem on the Doppler effect. I understand the first step which is to treat the bat as the source of the emitted sound, giving

View attachment 279012

And the second to treat the bat now as the observer, but instead of using f_b on the left the solution involves setting both frequencies to the reflected wave.
View attachment 279011
I understand there should 2 different variables here for the equation to make sense but I need help understanding why the second step involves setting the two frequencies the same. Thanks in advance!
As you correctly say, this is a 2-stage process. In stage-1 we find the observed frequency (##f_i##) with the insect as the observer). In stage-2 we treat ##f_i## as the source frequency because this is the frequency of the reflected signal sent from the insect to the bat.

Your final equation$$f_i = f_i (\frac {343 + v_b}{343 + v_i})$$is wrong. You need to give the final observed frequency (by the bat) a different symbol:$$f_{observed-by-bat} = f_i (\frac {343 + v_b}{343 + v_i})$$Can I suggest you watch this:
Edit - typo' corrected.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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